若8cos(π/4+α)×cos(π/4-α)=1,则sin4α+cos4α=那个sin4α是 sinα的四次幂 cos那个同理
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若8cos(π/4+α)×cos(π/4-α)=1,则sin4α+cos4α=那个sin4α是 sinα的四次幂 cos那个同理
若8cos(π/4+α)×cos(π/4-α)=1,则sin4α+cos4α=
那个sin4α是 sinα的四次幂 cos那个同理
若8cos(π/4+α)×cos(π/4-α)=1,则sin4α+cos4α=那个sin4α是 sinα的四次幂 cos那个同理
4[cos(π/2)+cos(2a)]=1
cos2a=1/4
sin^4a=(1-cos2a)^2/4=9/64
cos^4a=(1+cos2a)^2/4=25/64
sin^4a+cos^4a=34/64=17/32
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若8cos(π/4+α)×cos(π/4-α)=1,则sin4α+cos4α=那个sin4α是 sinα的四次幂 cos那个同理
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