有两个底面积相等的圆柱,一个圆柱高6DM,体积是48DM³,另一个圆柱高为5DM,体积是多少?
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/27 03:31:17
![有两个底面积相等的圆柱,一个圆柱高6DM,体积是48DM³,另一个圆柱高为5DM,体积是多少?](/uploads/image/z/5310997-61-7.jpg?t=%E6%9C%89%E4%B8%A4%E4%B8%AA%E5%BA%95%E9%9D%A2%E7%A7%AF%E7%9B%B8%E7%AD%89%E7%9A%84%E5%9C%86%E6%9F%B1%2C%E4%B8%80%E4%B8%AA%E5%9C%86%E6%9F%B1%E9%AB%986DM%2C%E4%BD%93%E7%A7%AF%E6%98%AF48DM%26%23179%3B%2C%E5%8F%A6%E4%B8%80%E4%B8%AA%E5%9C%86%E6%9F%B1%E9%AB%98%E4%B8%BA5DM%2C%E4%BD%93%E7%A7%AF%E6%98%AF%E5%A4%9A%E5%B0%91%3F)
有两个底面积相等的圆柱,一个圆柱高6DM,体积是48DM³,另一个圆柱高为5DM,体积是多少?
有两个底面积相等的圆柱,一个圆柱高6DM,体积是48DM³,另一个圆柱高为5DM,体积是多少?
有两个底面积相等的圆柱,一个圆柱高6DM,体积是48DM³,另一个圆柱高为5DM,体积是多少?
48÷6×5=40dm³
48除以6=8 5*8=40
6*S=48 S=8 v=s*h=8*5=40
用公式带入计算:
s=v÷h
=48÷6
=8(dm³)
v=sh
=8×5
=40(dm³)
40DM³,圆柱体的体积等于底面积乘以高
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圆柱的体积=底面积×高→底面积=体积÷高
这两个圆柱的底面积就是:48÷6=8(d㎡)
8×5=40(DM³)
.