求(2+5+8······+2000)-(1+4+7······+1999)的值.【简算】
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![求(2+5+8······+2000)-(1+4+7······+1999)的值.【简算】](/uploads/image/z/51526-46-6.jpg?t=%E6%B1%82%EF%BC%882%2B5%2B8%C2%B7%C2%B7%C2%B7%C2%B7%C2%B7%C2%B7%2B2000%EF%BC%89-%EF%BC%881%2B4%2B7%C2%B7%C2%B7%C2%B7%C2%B7%C2%B7%C2%B7%2B1999%EF%BC%89%E7%9A%84%E5%80%BC.%E3%80%90%E7%AE%80%E7%AE%97%E3%80%91)
求(2+5+8······+2000)-(1+4+7······+1999)的值.【简算】
求(2+5+8······+2000)-(1+4+7······+1999)的值.【简算】
求(2+5+8······+2000)-(1+4+7······+1999)的值.【简算】
很简单.
(2+5+8······+2000)-(1+4+7······+1999)
=(2-1)+(5-4)+(8-7)+.+(2000-1999)【一共有667个组合
=1+1+…+1 因此这有667个1】
=667
欢迎追问,
(2+5+8······+2000)-(1+4+7······+1999)
=(2-1)+(5-4)+(8-7)+。。。。+(2000-1999)
=1+1+。。。+1 (共667个1)
=667
667