matlab非线性拟合求参数问题,已知,t=[0,1,2,3,4,5,6,7,8,9];y=[127627,128453,129227,129988,130756,131448,132129,132802,133474,133972];y=a(1)/(1+(a(1)/a(2)-1)*exp(-1*a(3)*t));求参数a(1),a(2),a(3).麻烦给出详细解答代码,
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![matlab非线性拟合求参数问题,已知,t=[0,1,2,3,4,5,6,7,8,9];y=[127627,128453,129227,129988,130756,131448,132129,132802,133474,133972];y=a(1)/(1+(a(1)/a(2)-1)*exp(-1*a(3)*t));求参数a(1),a(2),a(3).麻烦给出详细解答代码,](/uploads/image/z/4479534-54-4.jpg?t=matlab%E9%9D%9E%E7%BA%BF%E6%80%A7%E6%8B%9F%E5%90%88%E6%B1%82%E5%8F%82%E6%95%B0%E9%97%AE%E9%A2%98%2C%E5%B7%B2%E7%9F%A5%2Ct%3D%5B0%2C1%2C2%2C3%2C4%2C5%2C6%2C7%2C8%2C9%5D%3By%3D%5B127627%2C128453%2C129227%2C129988%2C130756%2C131448%2C132129%2C132802%2C133474%2C133972%5D%3By%3Da%281%29%2F%281%2B%28a%281%29%2Fa%282%29-1%29%2Aexp%28-1%2Aa%283%29%2At%29%29%3B%E6%B1%82%E5%8F%82%E6%95%B0a%281%29%2Ca%282%29%2Ca%283%29.%E9%BA%BB%E7%83%A6%E7%BB%99%E5%87%BA%E8%AF%A6%E7%BB%86%E8%A7%A3%E7%AD%94%E4%BB%A3%E7%A0%81%2C)
matlab非线性拟合求参数问题,已知,t=[0,1,2,3,4,5,6,7,8,9];y=[127627,128453,129227,129988,130756,131448,132129,132802,133474,133972];y=a(1)/(1+(a(1)/a(2)-1)*exp(-1*a(3)*t));求参数a(1),a(2),a(3).麻烦给出详细解答代码,
matlab非线性拟合求参数问题,
已知,
t=[0,1,2,3,4,5,6,7,8,9];
y=[127627,128453,129227,129988,130756,131448,132129,132802,133474,133972];
y=a(1)/(1+(a(1)/a(2)-1)*exp(-1*a(3)*t));
求参数a(1),a(2),a(3).
麻烦给出详细解答代码,
matlab非线性拟合求参数问题,已知,t=[0,1,2,3,4,5,6,7,8,9];y=[127627,128453,129227,129988,130756,131448,132129,132802,133474,133972];y=a(1)/(1+(a(1)/a(2)-1)*exp(-1*a(3)*t));求参数a(1),a(2),a(3).麻烦给出详细解答代码,
>> t=[0,1,2,3,4,5,6,7,8,9]';
y=[127627,128453,129227,129988,130756,131448,132129,132802,133474,133972]';
ft_ = fittype('a1/(1+(a1/a2-1)*exp(-1*a3*t))',...
'dependent',{'y'},'independent',{'t'},...
'coefficients',{'a1','a2','a3'});
st=[8000 150000 0.2]
[curve,goodness]= fit(t,y,ft_,'Startpoint',st)
figure
plot(curve,'predobs',0.95);
hold on,plot(t,y,'b*')
st =
1.0e+005 *
0.0800 1.5000 0.0000
curve =
General model:
curve(t) = a1/(1+(a1/a2-1)*exp(-1*a3*t))
Coefficients (with 95% confidence bounds):
a1 = 1.468e+005 (1.437e+005,1.499e+005)
a2 = 1.276e+005 (1.276e+005,1.277e+005)
a3 = 0.05059 (0.04164,0.05954)
goodness =
sse:6.6191e+003
rsquare:0.9998
dfe:7
adjrsquare:0.9998
rmse:30.7503