有关MATLAB求解三元二次方程组的问题?>> syms x y z>> eq1=(18*(2*x - 30))/(5*((y - z)^2 + (x - 15)^2)^(1/2)) + (36*x)/(5*((y - 5)^2 + x^2)^(1/2));eq2=(18*(2*y - 10))/(5*((y - 5)^2 + x^2)^(1/2)) + (18*(2*y - 2*z))/(5*((y - z)^2 + (x - 15)^2
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![有关MATLAB求解三元二次方程组的问题?>> syms x y z>> eq1=(18*(2*x - 30))/(5*((y - z)^2 + (x - 15)^2)^(1/2)) + (36*x)/(5*((y - 5)^2 + x^2)^(1/2));eq2=(18*(2*y - 10))/(5*((y - 5)^2 + x^2)^(1/2)) + (18*(2*y - 2*z))/(5*((y - z)^2 + (x - 15)^2](/uploads/image/z/3965697-9-7.jpg?t=%E6%9C%89%E5%85%B3MATLAB%E6%B1%82%E8%A7%A3%E4%B8%89%E5%85%83%E4%BA%8C%E6%AC%A1%E6%96%B9%E7%A8%8B%E7%BB%84%E7%9A%84%E9%97%AE%E9%A2%98%3F%3E%3E+syms+x+y+z%3E%3E+eq1%3D%2818%2A%282%2Ax+-+30%29%29%2F%285%2A%28%28y+-+z%29%5E2+%2B+%28x+-+15%29%5E2%29%5E%281%2F2%29%29+%2B+%2836%2Ax%29%2F%285%2A%28%28y+-+5%29%5E2+%2B+x%5E2%29%5E%281%2F2%29%29%3Beq2%3D%2818%2A%282%2Ay+-+10%29%29%2F%285%2A%28%28y+-+5%29%5E2+%2B+x%5E2%29%5E%281%2F2%29%29+%2B+%2818%2A%282%2Ay+-+2%2Az%29%29%2F%285%2A%28%28y+-+z%29%5E2+%2B+%28x+-+15%29%5E2)
有关MATLAB求解三元二次方程组的问题?>> syms x y z>> eq1=(18*(2*x - 30))/(5*((y - z)^2 + (x - 15)^2)^(1/2)) + (36*x)/(5*((y - 5)^2 + x^2)^(1/2));eq2=(18*(2*y - 10))/(5*((y - 5)^2 + x^2)^(1/2)) + (18*(2*y - 2*z))/(5*((y - z)^2 + (x - 15)^2
有关MATLAB求解三元二次方程组的问题?
>> syms x y z
>> eq1=(18*(2*x - 30))/(5*((y - z)^2 + (x - 15)^2)^(1/2)) + (36*x)/(5*((y - 5)^2 + x^2)^(1/2));eq2=(18*(2*y - 10))/(5*((y - 5)^2 + x^2)^(1/2)) + (18*(2*y - 2*z))/(5*((y - z)^2 + (x - 15)^2)^(1/2)) + 36/5;eq3=(141*(2*z - 16))/(10*((z - 8)^2 + 25)^(1/2)) - (18*(2*y - 2*z))/(5*((y - z)^2 + (x - 15)^2)^(1/2));[x,y,z]=solve(eq1,eq2,eq3,'x','y','z')
请求大神看一下哪里有错误,我求不出结果
有关MATLAB求解三元二次方程组的问题?>> syms x y z>> eq1=(18*(2*x - 30))/(5*((y - z)^2 + (x - 15)^2)^(1/2)) + (36*x)/(5*((y - 5)^2 + x^2)^(1/2));eq2=(18*(2*y - 10))/(5*((y - 5)^2 + x^2)^(1/2)) + (18*(2*y - 2*z))/(5*((y - z)^2 + (x - 15)^2
>> syms x y z
>> eq1=(18*(2*x - 30))/(5*((y - z)^2 + (x - 15)^2)^(1/2)) + (36*x)/(5*((y - 5)^2 + x^2)^(1/2));
>> eq2=(18*(2*y - 10))/(5*((y - 5)^2 + x^2)^(1/2)) + (18*(2*y - 2*z))/(5*((y - z)^2 + (x - 15)^2)^(1/2)) + 36/5;
>> eq3=(141*(2*z - 16))/(10*((z - 8)^2 + 25)^(1/2)) - (18*(2*y - 2*z))/(5*((y - z)^2 + (x - 15)^2)^(1/2));
>> [x,y,z]=solve(eq1,eq2,eq3,'x','y','z')
经过在matlab7.0中尝试,发现没有问题,
x =
1861137696/586981625+2173/1080500*(-3+5*3^(1/2)+30/2173*2173^(1/2))^3-26751/54025*3^(1/2)-160506/117396325*2173^(1/2)+36791/540250*(-3+5*3^(1/2)+30/2173*2173^(1/2))^2
y =
13/2-5/2*3^(1/2)-15/2173*2173^(1/2)
z =
-6519/108050*(-3+5*3^(1/2)+30/2173*2173^(1/2))^2+451757/54025-2173/324150*(-3+5*3^(1/2)+30/2173*2173^(1/2))^3+17834/10805*3^(1/2)+107004/23479265*2173^(1/2)
这里得到的是符号解,转化为数值解;
>> x=subs(x),y=subs(y),z=subs(z)
x =
5.4593
y =
1.8481
z =
7.3564
>>