a/2=b/3=c/4=d/5不等于零,求(a+b+c+d)/(b+c)的值
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a/2=b/3=c/4=d/5不等于零,求(a+b+c+d)/(b+c)的值
a/2=b/3=c/4=d/5不等于零,求(a+b+c+d)/(b+c)的值
a/2=b/3=c/4=d/5不等于零,求(a+b+c+d)/(b+c)的值
设a/2=b/3=c/4=d/5=x
则a=2x,b=3x,c=4x,d=5x
(a+b+c+d)/(b+c)
=(2x+3x+4x+5x)/(3x+4x)
=14x/7x
=2
设a/2=b/3=c/4=d/5=k
a=2k;b=3k;c=4k;d=5k
(a+b+c+d)/(b+c)=(2k+3k+4k+5k)/(3k+4k)=2
设a/2=b/3=c/4=d/5=k≠0
∴a=2k b=3k c=4k d=5k
∴(a+b+c+d)/(b+c)=(2k+3k+4k+5k)/(3k+4k)=14k/7k=2
令a/2=b/3=c/4=d/5=k则a=2k b=3k c=4k d=5k
(a+b+c+d)/(b+c)
=(2k+3k+4k+5k)/(3k+4k)
=2
望采纳
令a/2=b/3=c/4=d/5=k,则有
a=2k,b=3k,c=4k,d=5k
所以,(a+b+c+d)/(b+c)=(2k+3k+4k+5k)/(3k+4k)=2
设:a/2=b/3=c/4=d/5=x,那么,
a=2x,b=3x,c=4x,d=5x,
a+b+c+d=2x+3x+4x+5x=14x,
b+c=3x+4x=7x,
故:结果为,14x/7x,即2
综上,值为2
把所有的数均用a表示
b=3a/2
c=2a
d=5a/2
于是该式=(a+3a/2+2a+5a/2)/(3a/2+2a)
=(1+3/2+2+5/2)/(3/2+2)
=2
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