matlab,plotx1=0:0.1:5;x2=1:0.1:6;x3=2:0.1:7;x=[x1;x2;x3];y=sin(x3);plot(x,y)x1=0:0.1:5;x2=1:0.1:6;x3=2:0.1:7;x=[x1;x2;x3];y=sin(x);plot(x,y)matlab初学者请教一下,第一幅图里面y=sin(x3)为何会有三条曲线,还有第二幅图为何会得
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/01 08:17:31
![matlab,plotx1=0:0.1:5;x2=1:0.1:6;x3=2:0.1:7;x=[x1;x2;x3];y=sin(x3);plot(x,y)x1=0:0.1:5;x2=1:0.1:6;x3=2:0.1:7;x=[x1;x2;x3];y=sin(x);plot(x,y)matlab初学者请教一下,第一幅图里面y=sin(x3)为何会有三条曲线,还有第二幅图为何会得](/uploads/image/z/2686511-47-1.jpg?t=matlab%2Cplotx1%3D0%3A0.1%3A5%3Bx2%3D1%3A0.1%3A6%3Bx3%3D2%3A0.1%3A7%3Bx%3D%5Bx1%3Bx2%3Bx3%5D%3By%3Dsin%28x3%29%3Bplot%28x%2Cy%29x1%3D0%3A0.1%3A5%3Bx2%3D1%3A0.1%3A6%3Bx3%3D2%3A0.1%3A7%3Bx%3D%5Bx1%3Bx2%3Bx3%5D%3By%3Dsin%28x%29%3Bplot%28x%2Cy%29matlab%E5%88%9D%E5%AD%A6%E8%80%85%E8%AF%B7%E6%95%99%E4%B8%80%E4%B8%8B%2C%E7%AC%AC%E4%B8%80%E5%B9%85%E5%9B%BE%E9%87%8C%E9%9D%A2y%3Dsin%28x3%29%E4%B8%BA%E4%BD%95%E4%BC%9A%E6%9C%89%E4%B8%89%E6%9D%A1%E6%9B%B2%E7%BA%BF%2C%E8%BF%98%E6%9C%89%E7%AC%AC%E4%BA%8C%E5%B9%85%E5%9B%BE%E4%B8%BA%E4%BD%95%E4%BC%9A%E5%BE%97)
matlab,plotx1=0:0.1:5;x2=1:0.1:6;x3=2:0.1:7;x=[x1;x2;x3];y=sin(x3);plot(x,y)x1=0:0.1:5;x2=1:0.1:6;x3=2:0.1:7;x=[x1;x2;x3];y=sin(x);plot(x,y)matlab初学者请教一下,第一幅图里面y=sin(x3)为何会有三条曲线,还有第二幅图为何会得
matlab,plot
x1=0:0.1:5;x2=1:0.1:6;x3=2:0.1:7;
x=[x1;x2;x3];
y=sin(x3);
plot(x,y)
x1=0:0.1:5;x2=1:0.1:6;x3=2:0.1:7;
x=[x1;x2;x3];
y=sin(x);
plot(x,y)
matlab初学者请教一下,第一幅图里面y=sin(x3)为何会有三条曲线,还有第二幅图为何会得到这样的曲线?
matlab,plotx1=0:0.1:5;x2=1:0.1:6;x3=2:0.1:7;x=[x1;x2;x3];y=sin(x3);plot(x,y)x1=0:0.1:5;x2=1:0.1:6;x3=2:0.1:7;x=[x1;x2;x3];y=sin(x);plot(x,y)matlab初学者请教一下,第一幅图里面y=sin(x3)为何会有三条曲线,还有第二幅图为何会得
第一个图,x1=x3-2,x2=x3-1
y=sin(x3);x=[x1;x2;x3];
plot(x,y) ,matlab矩阵作图都是按列描点,x1 x2 x3对应函数值都是sin(x3)只是x1=x3-2,x2=x3-1所以表现就是在x方向上的平移
第二幅图没什么好说的就是按列三个点一条曲线 共51条