数学分式方程式计算题1.若A/(x-5)+B/(x-2)=(5x-4)/(x^2-3x-10),试求A、B的值2.若1/R=1/R1+1/R2,且R1+R2不等於0,求R3.巳知a^2-6a+9与│b-1│互为相反数,则式子(a/b-b/a)/(a+b)的值为?4.巳知1/x-1/y,则分式(2x+3xy-2y)/(x-2xy
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![数学分式方程式计算题1.若A/(x-5)+B/(x-2)=(5x-4)/(x^2-3x-10),试求A、B的值2.若1/R=1/R1+1/R2,且R1+R2不等於0,求R3.巳知a^2-6a+9与│b-1│互为相反数,则式子(a/b-b/a)/(a+b)的值为?4.巳知1/x-1/y,则分式(2x+3xy-2y)/(x-2xy](/uploads/image/z/249894-54-4.jpg?t=%E6%95%B0%E5%AD%A6%E5%88%86%E5%BC%8F%E6%96%B9%E7%A8%8B%E5%BC%8F%E8%AE%A1%E7%AE%97%E9%A2%981.%E8%8B%A5A%2F%28x-5%29%2BB%2F%28x-2%29%3D%285x-4%29%2F%28x%5E2-3x-10%29%2C%E8%AF%95%E6%B1%82A%E3%80%81B%E7%9A%84%E5%80%BC2.%E8%8B%A51%2FR%3D1%2FR1%2B1%2FR2%2C%E4%B8%94R1%2BR2%E4%B8%8D%E7%AD%89%E6%96%BC0%2C%E6%B1%82R3.%E5%B7%B3%E7%9F%A5a%5E2-6a%2B9%E4%B8%8E%E2%94%82b-1%E2%94%82%E4%BA%92%E4%B8%BA%E7%9B%B8%E5%8F%8D%E6%95%B0%2C%E5%88%99%E5%BC%8F%E5%AD%90%28a%2Fb-b%2Fa%29%2F%28a%2Bb%29%E7%9A%84%E5%80%BC%E4%B8%BA%3F4.%E5%B7%B3%E7%9F%A51%2Fx-1%2Fy%2C%E5%88%99%E5%88%86%E5%BC%8F%282x%2B3xy-2y%29%2F%28x-2xy)
数学分式方程式计算题1.若A/(x-5)+B/(x-2)=(5x-4)/(x^2-3x-10),试求A、B的值2.若1/R=1/R1+1/R2,且R1+R2不等於0,求R3.巳知a^2-6a+9与│b-1│互为相反数,则式子(a/b-b/a)/(a+b)的值为?4.巳知1/x-1/y,则分式(2x+3xy-2y)/(x-2xy
数学分式方程式计算题
1.若A/(x-5)+B/(x-2)=(5x-4)/(x^2-3x-10),试求A、B的值
2.若1/R=1/R1+1/R2,且R1+R2不等於0,求R
3.巳知a^2-6a+9与│b-1│互为相反数,则式子(a/b-b/a)/(a+b)的值为?
4.巳知1/x-1/y,则分式(2x+3xy-2y)/(x-2xy-y)的值为?
5.解分式方程:(x^2+7x-8)/(x-1)+(x^2+x+3)/(x+2)+(2x^2-x+7)/(x+3)=4x,求x的值
数学分式方程式计算题1.若A/(x-5)+B/(x-2)=(5x-4)/(x^2-3x-10),试求A、B的值2.若1/R=1/R1+1/R2,且R1+R2不等於0,求R3.巳知a^2-6a+9与│b-1│互为相反数,则式子(a/b-b/a)/(a+b)的值为?4.巳知1/x-1/y,则分式(2x+3xy-2y)/(x-2xy
我是收到团队求助来答问的
1..若A/(x-5)+B/(x-2)=(5x-4)/(x^2-3x-10),试求A、B的值
改过的答:
你的问题是不是有问题?
因为这一类题目应该是这样子的吧
A/(x-5)+B/(x-2)=(5x-4)/(x^2-7x+10)
两边相乘(X-5)(X-2)
A(X-2)+B(X-5) = (5X-4)(X-5)(X-2)/ (X^2-7X+10)
把相同的种类归在一起,变成这样子.
(A+B)X - (2A+5B) = (5X-4)(X-5)(X-2) / (X-5)(X-2)
(A+B)X - (2A+5B) = (5X-4)
(A+B)X = 5 X
所以A+B=5,然后改A=5-B
-2A-5B= -4
-2(5-B)-5B=-4
-10+2B-5B=-4
-3B=6
B=-2
A=5-(-2)
A=7
这一类题目就是这么做,
2.若1/R=1/R1+1/R2,且R1+R2不等於0,求R
答:
1/R=1/r1+1/r2=(r1+r2)/r1r2
R=r1r2/(r1+r2)
3.巳知a^2-6a+9与│b-1│互为相反数,则式子(a/b-b/a)/(a+b)的值为?
答:
因为a^2-6a+9与|b-1|互为相反数
则a^-6a+9+|b-1|=0
(a-3)^2+|b-1|=0
则a-3=0
a=3
b-1=0
b=1
(a/b-b/a)÷(a+b)=2/3
4.巳知1/x-1/y,则分式(2x+3xy-2y)/(x-2xy-y)的值为?
这个问题有点怪,给个比方
已知1/x-1/y=3(这才能找到答案吧)
所以把问题改点
已知1/x-1/y=3,则分式(2x+3xy-2y)/(x-2xy-y)的值为?
答:
1/x-1/y=3
(y-x)/xy=3
y-x=3xy
x-y=-3xy
所以(2x+3xy-2y)/(x-2xy-y)
=[2(x-y)+3xy]/[(x-y)-2xy]
=-3xy/-5xy
=3/5
5.解分式方程:(x^2+7x-8)/(x-1)+(x^2+x+3)/(x+2)+(2x^2-x+7)/(x+3)=4x,求x的值
这题过度简单啦,自己做哈
就这样.