2道初2分式计算题1,已知b-1的相反数等于它本身,ab与-2互为相反数,求ab分之1+(a+1)(b+1)分之1+……+(a+2009)(b+2009)分之1的值2,已知(x-1)(x-2)分之3x-4=x-1分之A+x-2分之B,求A,B的值
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![2道初2分式计算题1,已知b-1的相反数等于它本身,ab与-2互为相反数,求ab分之1+(a+1)(b+1)分之1+……+(a+2009)(b+2009)分之1的值2,已知(x-1)(x-2)分之3x-4=x-1分之A+x-2分之B,求A,B的值](/uploads/image/z/225712-64-2.jpg?t=2%E9%81%93%E5%88%9D2%E5%88%86%E5%BC%8F%E8%AE%A1%E7%AE%97%E9%A2%981%2C%E5%B7%B2%E7%9F%A5b-1%E7%9A%84%E7%9B%B8%E5%8F%8D%E6%95%B0%E7%AD%89%E4%BA%8E%E5%AE%83%E6%9C%AC%E8%BA%AB%2Cab%E4%B8%8E-2%E4%BA%92%E4%B8%BA%E7%9B%B8%E5%8F%8D%E6%95%B0%2C%E6%B1%82ab%E5%88%86%E4%B9%8B1%2B%EF%BC%88a%2B1%29%28b%2B1%29%E5%88%86%E4%B9%8B1%2B%E2%80%A6%E2%80%A6%2B%EF%BC%88a%2B2009%29%28b%2B2009%29%E5%88%86%E4%B9%8B1%E7%9A%84%E5%80%BC2%2C%E5%B7%B2%E7%9F%A5%EF%BC%88x-1%29%28x-2%29%E5%88%86%E4%B9%8B3x-4%3Dx-1%E5%88%86%E4%B9%8BA%2Bx-2%E5%88%86%E4%B9%8BB%2C%E6%B1%82A%2CB%E7%9A%84%E5%80%BC)
2道初2分式计算题1,已知b-1的相反数等于它本身,ab与-2互为相反数,求ab分之1+(a+1)(b+1)分之1+……+(a+2009)(b+2009)分之1的值2,已知(x-1)(x-2)分之3x-4=x-1分之A+x-2分之B,求A,B的值
2道初2分式计算题
1,已知b-1的相反数等于它本身,ab与-2互为相反数,求ab分之1+(a+1)(b+1)分之1+……+(a+2009)(b+2009)分之1的值
2,已知(x-1)(x-2)分之3x-4=x-1分之A+x-2分之B,求A,B的值
2道初2分式计算题1,已知b-1的相反数等于它本身,ab与-2互为相反数,求ab分之1+(a+1)(b+1)分之1+……+(a+2009)(b+2009)分之1的值2,已知(x-1)(x-2)分之3x-4=x-1分之A+x-2分之B,求A,B的值
1,已知b-1的相反数等于它本身,ab与-2互为相反数,求ab分之1+(a+1)(b+1)分之1+……+(a+2009)(b+2009)分之1的值
-(b-1)=b-1,解得b=1
ab+(-2)=0,解得:a=2
原式=1/1*2+1/2*3+...+1/2010*2011
=1-1/2+1/2-1/3+...+1/2010-1/2011
=1-1/2011
=2010/2011
2,已知(x-1)(x-2)分之3x-4=x-1分之A+x-2分之B,求A,B的值
解:(3x-4)/((x-1)(x-2))=a/(x-1)+b/(x-2)
(3x-4)/((x-1)(x-2))=(a(x-2)+b(x-1))/((x-1)(x-2))
(3x-4)/((x-1)(x-2))=(ax-2a+bx-b)/((x-1)(x-2))
(3x-4)/((x-1)(x-2))=((ax+bx)-(2a+b))/((x-1)(x-2))
(3x-4)/((x-1)(x-2))= ((a+b)x-(2a+b))/((x-1)(x-2))
a+b=3 ,2a+b=4
a=1 ,b=2