为测定某铜银合金的成分,将6.2g合金溶于40mL3.5mol/L的稀硝酸中,待合金完全溶解后,.为测定某铜银合金的成分,将6.2g合金溶于40mL3.5mol/L的稀硝酸中,待合金完全溶解后,并测得溶液中H+浓度为1mol/L.
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![为测定某铜银合金的成分,将6.2g合金溶于40mL3.5mol/L的稀硝酸中,待合金完全溶解后,.为测定某铜银合金的成分,将6.2g合金溶于40mL3.5mol/L的稀硝酸中,待合金完全溶解后,并测得溶液中H+浓度为1mol/L.](/uploads/image/z/2192940-36-0.jpg?t=%E4%B8%BA%E6%B5%8B%E5%AE%9A%E6%9F%90%E9%93%9C%E9%93%B6%E5%90%88%E9%87%91%E7%9A%84%E6%88%90%E5%88%86%2C%E5%B0%866.2g%E5%90%88%E9%87%91%E6%BA%B6%E4%BA%8E40mL3.5mol%2FL%E7%9A%84%E7%A8%80%E7%A1%9D%E9%85%B8%E4%B8%AD%2C%E5%BE%85%E5%90%88%E9%87%91%E5%AE%8C%E5%85%A8%E6%BA%B6%E8%A7%A3%E5%90%8E%2C.%E4%B8%BA%E6%B5%8B%E5%AE%9A%E6%9F%90%E9%93%9C%E9%93%B6%E5%90%88%E9%87%91%E7%9A%84%E6%88%90%E5%88%86%2C%E5%B0%866.2g%E5%90%88%E9%87%91%E6%BA%B6%E4%BA%8E40mL3.5mol%2FL%E7%9A%84%E7%A8%80%E7%A1%9D%E9%85%B8%E4%B8%AD%2C%E5%BE%85%E5%90%88%E9%87%91%E5%AE%8C%E5%85%A8%E6%BA%B6%E8%A7%A3%E5%90%8E%2C%E5%B9%B6%E6%B5%8B%E5%BE%97%E6%BA%B6%E6%B6%B2%E4%B8%ADH%2B%E6%B5%93%E5%BA%A6%E4%B8%BA1mol%2FL.)
为测定某铜银合金的成分,将6.2g合金溶于40mL3.5mol/L的稀硝酸中,待合金完全溶解后,.为测定某铜银合金的成分,将6.2g合金溶于40mL3.5mol/L的稀硝酸中,待合金完全溶解后,并测得溶液中H+浓度为1mol/L.
为测定某铜银合金的成分,将6.2g合金溶于40mL3.5mol/L的稀硝酸中,待合金完全溶解后,.
为测定某铜银合金的成分,将6.2g合金溶于40mL3.5mol/L的稀硝酸中,待合金完全溶解后,并测得溶液中H+浓度为1mol/L.假设反应后溶液的体积仍为40mL,试计算:
(1)反应中被还原硝酸的物质的量.
(2)在合金中银的质量分数.
复制党神马的就不要来了.
为测定某铜银合金的成分,将6.2g合金溶于40mL3.5mol/L的稀硝酸中,待合金完全溶解后,.为测定某铜银合金的成分,将6.2g合金溶于40mL3.5mol/L的稀硝酸中,待合金完全溶解后,并测得溶液中H+浓度为1mol/L.
(1)根据:Cu+4HNO3=Cu(NO3)2+2NO2↑+2H2O
3Cu+8HNO3=3Cu(NO3)2+2NO↑+4H2O
Ag+2HNO3=AgNO3+NO2↑+H2O
3Ag+4HNO3=3AgNO3+NO↑+2H2O
可知:被还原的n(HNO3)=n(NO2)+n(NO)=6.72L/22.4L/mol=0.3mol
(2)由题意可知:反应后的溶液中c(HNO3)=1mol/L
反应中消耗:
n(HNO3)=0.3mol+2n(Cu(NO3)2)+n(AgNO3)
=0.3mol+2n(Cu)+n(Ag)
=0.08L*(13.5mol/L-1mol/L)=1mol
则:2n(Cu)+n(Ag)=0.7mol
又据:64n(Cu)+108n(Ag)=30
解得:n(Cu)=0.3mol; n(Ag)=0.1mol
合金中银的质量分数=0.1*108/30=36%