已知tan2θ=-2根号2,π/4<θ<π/2.求(2cos²θ/2-sinθ-1)/[根号2sin(π/4+θ)]
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已知tan2θ=-2根号2,π/4<θ<π/2.求(2cos²θ/2-sinθ-1)/[根号2sin(π/4+θ)]
已知tan2θ=-2根号2,π/4<θ<π/2.求(2cos²θ/2-sinθ-1)/[根号2sin(π/4+θ)]
已知tan2θ=-2根号2,π/4<θ<π/2.求(2cos²θ/2-sinθ-1)/[根号2sin(π/4+θ)]
因为 派/2
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已知tan2θ=-2根号2,π/4<θ<π/2.求(2cos²θ/2-sinθ-1)/[根号2sin(π/4+θ)]
已知tan2θ=2根号2,0就是[sinθ+2sin^2(θ/2)-1]/[(根号2)cos(π/4-θ)]这样可以了吗
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