lim x→o (tanx-x)/(x-sinx)极限怎么求呀?
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lim x→o (tanx-x)/(x-sinx)极限怎么求呀?
lim x→o (tanx-x)/(x-sinx)极限怎么求呀?
lim x→o (tanx-x)/(x-sinx)极限怎么求呀?
原式=lim(x->0)[(sec²x-1)/(1-cosx) (0/0型极限,应用洛必达法则)
=lim(x->0)(2sec²xtanx/sinx) (0/0型极限,应用洛必达法则)
=lim(x->0)(2/cos³x)
=2
lim x→o (tanx-x)/(x-sinx)极限怎么求呀?
lim x→o (tanx-x)/(x-sinx)极限怎么求(不用罗必塔法则)
lim(x→0) x-tanx/x+tanx=?
lim(x→0)x-tanx/x+tanx=
lim(x→0) tanx/x=
lim x→0 x/tanx
lim x→0((x+ sinx)/tanx)
lim(x→0) (1+tanx)^cotx
lim(X->0)(tanX一SinX)/(X^3)=
lim x→0 (tanx-x)/x³=?
lim(x→0)(secx)^2tanx
lim(x→ 0)(tanx-sinx)/xsinx^2
lim(X→ π/2)tanx/tan3x
lim(x->1) x^(1/(1-x)) lim(x->0) x^(tanx)的值
tanx除以x的极限利用性质2.10及lim(x→0)sinx/x=1,证明:lim(x→0)tanx/x=1
求极限:lim(x→0)(tanx-sinx)/x^3
求极限lim(x→0)(tanx-sinx)/(x-sinx)
x→+0,lim(1/x)^(tanx)=?