用因式分解解方程(有过程):(1)9y^2=(y-z)^2 (2)(4x-1)^2=(1-5x)^2 (3)x^3-4x^2+4x=0
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/02 05:36:11
![用因式分解解方程(有过程):(1)9y^2=(y-z)^2 (2)(4x-1)^2=(1-5x)^2 (3)x^3-4x^2+4x=0](/uploads/image/z/1810651-67-1.jpg?t=%E7%94%A8%E5%9B%A0%E5%BC%8F%E5%88%86%E8%A7%A3%E8%A7%A3%E6%96%B9%E7%A8%8B%EF%BC%88%E6%9C%89%E8%BF%87%E7%A8%8B%EF%BC%89%EF%BC%9A%EF%BC%881%EF%BC%899y%5E2%3D%28y-z%29%5E2+%EF%BC%882%EF%BC%89%EF%BC%884x-1%EF%BC%89%5E2%3D%281-5x%29%5E2+%283%29x%5E3-4x%5E2%2B4x%3D0)
用因式分解解方程(有过程):(1)9y^2=(y-z)^2 (2)(4x-1)^2=(1-5x)^2 (3)x^3-4x^2+4x=0
用因式分解解方程(有过程):(1)9y^2=(y-z)^2 (2)(4x-1)^2=(1-5x)^2 (3)x^3-4x^2+4x=0
用因式分解解方程(有过程):(1)9y^2=(y-z)^2 (2)(4x-1)^2=(1-5x)^2 (3)x^3-4x^2+4x=0
9y^2=(y-z)^2
9y^2-(y-z)^2=0
(3y+y-z)(3y-y+z)=0
(4y-z)(2y+z)=0
4y-z=0.2y+z=0
y=z/4,y=-z/2
(2)(4x-1)^2=(1-5x)^2
(4x-1)^2-(1-5x)^2=0
(4x-1+1-5x)(4x-1-1+5x)=0
(-x)(9x-2)=0
-x=0,9x-2=0
x=0,x=2/9
(3)x^3-4x^2+4x=0
x(x^2-4x+4)=0
x(x-2)^2=0
x=0,x-2=0
x=0,x=2
你能明白,赞同
yun
第(1)条方程有2个未知数,没有唯一解
第(2)条方程不用因式分解,直接用4x-1=±(1-5x)就可以了
第(3)条方程可分解为:x(x-2)^2=0,解为0或2
1. 9y^2-(y-z)^2=0
[3y+(y-z)][3y-(y-z)] =0
(4y-z)(2y+z)=0
4y-z=0 y1=1/4z
2y+z=0 y2=-1/2z
2. (4x-1)^2-(1-5x)^2=0
(4x-1+ 1-5x)[4x-1-(1-5x)]=0
...
全部展开
1. 9y^2-(y-z)^2=0
[3y+(y-z)][3y-(y-z)] =0
(4y-z)(2y+z)=0
4y-z=0 y1=1/4z
2y+z=0 y2=-1/2z
2. (4x-1)^2-(1-5x)^2=0
(4x-1+ 1-5x)[4x-1-(1-5x)]=0
-x*(9x+2)=0
x1=0
x2=-2/9
3. x^3-4x^2+4x=0
x(x^2-4x+4)=0
x(x-2)^2=0
x1=0 x2=x3=2
收起