关于存款的数学问题I now have $11,000 in the bank earning interest of .75% per month. I need $21,000 to make a down payment on a house. I can save an additional $100 per month. How long will it take me to accumulate the $21,000? 大概译文
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![关于存款的数学问题I now have $11,000 in the bank earning interest of .75% per month. I need $21,000 to make a down payment on a house. I can save an additional $100 per month. How long will it take me to accumulate the $21,000? 大概译文](/uploads/image/z/1760737-49-7.jpg?t=%E5%85%B3%E4%BA%8E%E5%AD%98%E6%AC%BE%E7%9A%84%E6%95%B0%E5%AD%A6%E9%97%AE%E9%A2%98I+now+have+%2411%2C000+in+the+bank+earning+interest+of+.75%25+per+month.+I+need+%2421%2C000+to+make+a+down+payment+on+a+house.+I+can+save+an+additional+%24100+per+month.+How+long+will+it+take+me+to+accumulate+the+%2421%2C000%3F+%E5%A4%A7%E6%A6%82%E8%AF%91%E6%96%87)
关于存款的数学问题I now have $11,000 in the bank earning interest of .75% per month. I need $21,000 to make a down payment on a house. I can save an additional $100 per month. How long will it take me to accumulate the $21,000? 大概译文
关于存款的数学问题
I now have $11,000 in the bank earning interest of .75% per month. I need $21,000 to make a down payment on a house. I can save an additional $100 per month. How long will it take me to accumulate the $21,000?
大概译文:
我现在有$11,000,每月0.75%的银行赚取利息.我需要买21000美元作首付的房子.我可以每月多存下100元.需要多长时间我才能有21000美元?
保留两位有效小数
关于存款的数学问题I now have $11,000 in the bank earning interest of .75% per month. I need $21,000 to make a down payment on a house. I can save an additional $100 per month. How long will it take me to accumulate the $21,000? 大概译文
假设经t个月能实现
令q=0.75%,则有:
11000*(1+q)^t+100(1+q)^t+100(1+q)^(t-1)+...+100=21000
利用等比数列求和,可解得:
t=45.53
根据实际意义,应取46个月
复利计算问题
11000×(1+0.75)n次幂+100×(1+0.75)1次幂+100×(1+0.75)2次幂+……+100×(1+0.75)n次幂≥21000即可。
有公式的
http://baike.baidu.com/link?url=GYwFuIiV_tL-sOdeDNTtiG2LWH5KTVCiRhBCx0jVf0bQTZhqwHCAMxGz6yCYaFLl
财务分析里面的等额多次支付问题
月利率=0.75% 年利率=[(1+0.0075)^12]-1=0.938
假如你存n年吧
固定资金11000的收益:11000*[1+0.938]^n
每月存款收益 1000*[(1+0.0075)^12n - 1]/0.0075
两者之和是21000
求取n