中括号(x-2/x+2)的平方-2+(x+2/x-2)的平方中括号除以(x-2/x+2-x+2/x-2)
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/04 18:58:45
![中括号(x-2/x+2)的平方-2+(x+2/x-2)的平方中括号除以(x-2/x+2-x+2/x-2)](/uploads/image/z/1750344-24-4.jpg?t=%E4%B8%AD%E6%8B%AC%E5%8F%B7%EF%BC%88x-2%2Fx%2B2%EF%BC%89%E7%9A%84%E5%B9%B3%E6%96%B9-2%2B%EF%BC%88x%2B2%2Fx-2%EF%BC%89%E7%9A%84%E5%B9%B3%E6%96%B9%E4%B8%AD%E6%8B%AC%E5%8F%B7%E9%99%A4%E4%BB%A5%EF%BC%88x-2%2Fx%2B2-x%2B2%2Fx-2%EF%BC%89)
中括号(x-2/x+2)的平方-2+(x+2/x-2)的平方中括号除以(x-2/x+2-x+2/x-2)
中括号(x-2/x+2)的平方-2+(x+2/x-2)的平方中括号除以(x-2/x+2-x+2/x-2)
中括号(x-2/x+2)的平方-2+(x+2/x-2)的平方中括号除以(x-2/x+2-x+2/x-2)
中括号(x-2/x+2)的平方-2+(x+2/x-2)的平方中括号除以(x-2/x+2-x+2/x-2)
={(x-2)/(x+2)]^2-2+[(x+2)/(x-2)]^2}/[(x-2)/(x+2)-(x+2)/(x-2)
={[(x-2)/(x+2)-(x+2)/(x-2)]^2}/{[(x-2)^2-(x+2)^2]/[(x+2)(x-2)]}
={[(x-2)/(x+2)-(x+2)/(x-2)]^2}×(x+2)(x-2)/[(x-2)^2-(x+2)^2]
=({[(x-2)^2-(x+2)^2]/[(x+2)(x-2)]}^2)×(x+2)(x-2)/[(x-2)^2-(x+2)^2]
={[(x-2)^2-(x+2)^2]^2}/[(x+2)(x-2)]}/[(x-2)^2-(x+2)^2]
={[(x-2)^2-(x+2)^2]^2}/{[(x+2)(x-2)[(x-2)^2-(x+2)^2]}
=[(x-2)^2-(x+2)^2]/[(x+2)(x-2)]
=[(x-2)+(x+2)][(x-2)-(x+2)]/[(x+2)(x-2)]
=[2x(-4)]/[(x+2)(x-2)]
=-8x/[(x+2)(x-2)]
=0/{[(x^2+2x-2)/x]^2-2+[(x^2-2x+2)/x]^2}
=0