极限求值谢谢
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/29 01:07:59
![极限求值谢谢](/uploads/image/z/15087406-22-6.jpg?t=%E6%9E%81%E9%99%90%E6%B1%82%E5%80%BC%E8%B0%A2%E8%B0%A2)
极限求值谢谢
极限求值谢谢
极限求值谢谢
原式=limx->-1 (x+1)(x-1)/(x+2)(x+1)
=limx->-1 (x-1)/(x+2)
=-2
lim(x→ -1) (x^2-1)/(x^2+3x+2)
= lim(x→ -1) (x+1)(x-1)/(x+1)(x+2)
= lim(x→ -1) (x-1)/(x+2)
= (-1-1)/(-1+2)
= -2
希望你能采纳,不懂可追问。