把4.6g的纳慢慢地放进10g的水裏,当反应完成后,剩下的溶剂的总质量会是多少?另付上英文原题:4.6g of sodium are added slowly to 10g of water in a small dish.What is the total mass of the solution left when the reaction is
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![把4.6g的纳慢慢地放进10g的水裏,当反应完成后,剩下的溶剂的总质量会是多少?另付上英文原题:4.6g of sodium are added slowly to 10g of water in a small dish.What is the total mass of the solution left when the reaction is](/uploads/image/z/14547398-14-8.jpg?t=%E6%8A%8A4.6g%E7%9A%84%E7%BA%B3%E6%85%A2%E6%85%A2%E5%9C%B0%E6%94%BE%E8%BF%9B10g%E7%9A%84%E6%B0%B4%E8%A3%8F%2C%E5%BD%93%E5%8F%8D%E5%BA%94%E5%AE%8C%E6%88%90%E5%90%8E%2C%E5%89%A9%E4%B8%8B%E7%9A%84%E6%BA%B6%E5%89%82%E7%9A%84%E6%80%BB%E8%B4%A8%E9%87%8F%E4%BC%9A%E6%98%AF%E5%A4%9A%E5%B0%91%3F%E5%8F%A6%E4%BB%98%E4%B8%8A%E8%8B%B1%E6%96%87%E5%8E%9F%E9%A2%98%3A4.6g+of+sodium+are+added+slowly+to+10g+of+water+in+a+small+dish.What+is+the+total+mass+of+the+solution+left+when+the+reaction+is)
把4.6g的纳慢慢地放进10g的水裏,当反应完成后,剩下的溶剂的总质量会是多少?另付上英文原题:4.6g of sodium are added slowly to 10g of water in a small dish.What is the total mass of the solution left when the reaction is
把4.6g的纳慢慢地放进10g的水裏,当反应完成后,剩下的溶剂的总质量会是多少?
另付上英文原题:
4.6g of sodium are added slowly to 10g of water in a small dish.What is the total mass of the solution left when the reaction is complete?
把4.6g的纳慢慢地放进10g的水裏,当反应完成后,剩下的溶剂的总质量会是多少?另付上英文原题:4.6g of sodium are added slowly to 10g of water in a small dish.What is the total mass of the solution left when the reaction is
因为4.6g Na与3.6g 水才能完全反应完
设:共有xg水被反应.
2Na+2H2o==2NaOH+H2
46 36
4.6 X
46/4.6=36/X
解得X=3.6
SO 溶剂H2O还剩10-3.6=6.4 g
溶剂就是水,所以还是10G
4.6克的钠是溶质 10克的水是溶剂 所以溶剂的总质量是10克
反映剩下的是氢氧化钠溶液
溶剂是水 应该是10g水减去反映消耗的的水3.6g 所以溶剂问6.4g
2Na+2H2O=2NaOH+H2
纳在水里发生如下反应2Na+2H2O=2NaOH+H2 根据方程4.6克Na消耗3.6克水,还有10-3.6=6.4克水作为NaOH溶液的溶剂。
2Na---2H2O---H2
反应消耗水3.6g
跑掉H20.2g
剩余为溶剂10-3.6-0.2=6.2g
2Na---2H2O---H2
反应消耗水3.6g
跑掉H20.2g
剩余为溶剂10-3.6-0.2=6.2g
因为4.6g Na与3.6g 水才能完全反应完
设:共有xg水被反应.
2Na+2H2o==2NaOH+H2
46 36
4.6 X
46/4.6=36/X
解得X=3.6
SO 溶剂H2O还剩10-3.6=6.4 g
同上,6.4克