eq1=sym('1-s-C*g-D*w=0'); eq2=sym('a+w*(1-E*g-F*w)=0'); [g,w]=solve(eq1,eq2); [g,w]运行出结果是ans =[ 1-C*g+1/2*D*(-1+E*g-(1-2*E*g+E^2*g^2+4*F*a)^(1/2))/F,-1/2*(-1+E*g-(1-2*E*g+E^2*g^2+4*F*a)^(1/2))/F][ 1-C*g+1/2*D*(-1+E*g+(1-2*E*g+E^2*g^2+4*F*
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/30 20:32:10
![eq1=sym('1-s-C*g-D*w=0'); eq2=sym('a+w*(1-E*g-F*w)=0'); [g,w]=solve(eq1,eq2); [g,w]运行出结果是ans =[ 1-C*g+1/2*D*(-1+E*g-(1-2*E*g+E^2*g^2+4*F*a)^(1/2))/F,-1/2*(-1+E*g-(1-2*E*g+E^2*g^2+4*F*a)^(1/2))/F][ 1-C*g+1/2*D*(-1+E*g+(1-2*E*g+E^2*g^2+4*F*](/uploads/image/z/13559731-43-1.jpg?t=eq1%3Dsym%28%271-s-C%2Ag-D%2Aw%3D0%27%29%3B+eq2%3Dsym%28%27a%2Bw%2A%281-E%2Ag-F%2Aw%29%3D0%27%29%3B+%5Bg%2Cw%5D%3Dsolve%28eq1%2Ceq2%29%3B+%5Bg%2Cw%5D%E8%BF%90%E8%A1%8C%E5%87%BA%E7%BB%93%E6%9E%9C%E6%98%AFans+%3D%5B+1-C%2Ag%2B1%2F2%2AD%2A%28-1%2BE%2Ag-%281-2%2AE%2Ag%2BE%5E2%2Ag%5E2%2B4%2AF%2Aa%29%5E%281%2F2%29%29%2FF%2C-1%2F2%2A%28-1%2BE%2Ag-%281-2%2AE%2Ag%2BE%5E2%2Ag%5E2%2B4%2AF%2Aa%29%5E%281%2F2%29%29%2FF%5D%5B+1-C%2Ag%2B1%2F2%2AD%2A%28-1%2BE%2Ag%2B%281-2%2AE%2Ag%2BE%5E2%2Ag%5E2%2B4%2AF%2A)
eq1=sym('1-s-C*g-D*w=0'); eq2=sym('a+w*(1-E*g-F*w)=0'); [g,w]=solve(eq1,eq2); [g,w]运行出结果是ans =[ 1-C*g+1/2*D*(-1+E*g-(1-2*E*g+E^2*g^2+4*F*a)^(1/2))/F,-1/2*(-1+E*g-(1-2*E*g+E^2*g^2+4*F*a)^(1/2))/F][ 1-C*g+1/2*D*(-1+E*g+(1-2*E*g+E^2*g^2+4*F*
eq1=sym('1-s-C*g-D*w=0'); eq2=sym('a+w*(1-E*g-F*w)=0'); [g,w]=solve(eq1,eq2); [g,w]
运行出结果是ans =
[ 1-C*g+1/2*D*(-1+E*g-(1-2*E*g+E^2*g^2+4*F*a)^(1/2))/F,-1/2*(-1+E*g-(1-2*E*g+E^2*g^2+4*F*a)^(1/2))/F]
[ 1-C*g+1/2*D*(-1+E*g+(1-2*E*g+E^2*g^2+4*F*a)^(1/2))/F,-1/2*(-1+E*g+(1-2*E*g+E^2*g^2+4*F*a)^(1/2))/F]:
怎么还含有未知数g
eq1=sym('1-s-C*g-D*w=0'); eq2=sym('a+w*(1-E*g-F*w)=0'); [g,w]=solve(eq1,eq2); [g,w]运行出结果是ans =[ 1-C*g+1/2*D*(-1+E*g-(1-2*E*g+E^2*g^2+4*F*a)^(1/2))/F,-1/2*(-1+E*g-(1-2*E*g+E^2*g^2+4*F*a)^(1/2))/F][ 1-C*g+1/2*D*(-1+E*g+(1-2*E*g+E^2*g^2+4*F*
[ 1-C*g+1/2*D*(-1+E*g+(1-2*E*g+E^2*g^2+4*F*a)^(1W=Fscosa 功是标量 功的单位:焦耳(J) 1J=1N*m 当 0<= a <派/2
咱桑夏
应该是[ 1-C*g+1/2*D*(-1+E*g+(1-2*E*g+E^2*g^2+4*F*a)^(1/2))/F, -1/2*(-1+E*g+(1-2*E*g+E^2*g^2+4*F*a)^(1/2))/F]: