︱y+z︳2013+ ︳z+x︳2013 + ︳x+y︳2012 =2的整数解数组(x,y,z)有( )组.正确的应该是(y+z)^2013+(z+x)^2013 + (x+y+1)^2 =2的整数解数组(x,z)有( )组.希望有人能尽快解答,万谢!
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/06 20:44:43
![︱y+z︳2013+ ︳z+x︳2013 + ︳x+y︳2012 =2的整数解数组(x,y,z)有( )组.正确的应该是(y+z)^2013+(z+x)^2013 + (x+y+1)^2 =2的整数解数组(x,z)有( )组.希望有人能尽快解答,万谢!](/uploads/image/z/13357857-57-7.jpg?t=%EF%B8%B1y%2Bz%EF%B8%B32013%2B+%EF%B8%B3z%2Bx%EF%B8%B32013+%2B+%EF%B8%B3x%2By%EF%B8%B32012+%3D2%E7%9A%84%E6%95%B4%E6%95%B0%E8%A7%A3%E6%95%B0%E7%BB%84%28x%2Cy%2Cz%29%E6%9C%89%28+%29%E7%BB%84.%E6%AD%A3%E7%A1%AE%E7%9A%84%E5%BA%94%E8%AF%A5%E6%98%AF%28y%2Bz%29%5E2013%2B%28z%2Bx%29%5E2013+%2B+%28x%2By%2B1%29%5E2+%3D2%E7%9A%84%E6%95%B4%E6%95%B0%E8%A7%A3%E6%95%B0%E7%BB%84%EF%BC%88x%EF%BC%8Cz%EF%BC%89%E6%9C%89%EF%BC%88+%EF%BC%89%E7%BB%84.%E5%B8%8C%E6%9C%9B%E6%9C%89%E4%BA%BA%E8%83%BD%E5%B0%BD%E5%BF%AB%E8%A7%A3%E7%AD%94%EF%BC%8C%E4%B8%87%E8%B0%A2%EF%BC%81)
︱y+z︳2013+ ︳z+x︳2013 + ︳x+y︳2012 =2的整数解数组(x,y,z)有( )组.正确的应该是(y+z)^2013+(z+x)^2013 + (x+y+1)^2 =2的整数解数组(x,z)有( )组.希望有人能尽快解答,万谢!
︱y+z︳2013+ ︳z+x︳2013 + ︳x+y︳2012 =2的整数解数组(x,y,z)有( )组.
正确的应该是
(y+z)^2013+(z+x)^2013 + (x+y+1)^2 =2的整数解数组(x,z)有( )组.
希望有人能尽快解答,万谢!
︱y+z︳2013+ ︳z+x︳2013 + ︳x+y︳2012 =2的整数解数组(x,y,z)有( )组.正确的应该是(y+z)^2013+(z+x)^2013 + (x+y+1)^2 =2的整数解数组(x,z)有( )组.希望有人能尽快解答,万谢!
(y+z)^2013+(z+x)^2013 + (x+y+1)^2 =2的整数解数组(x,y,z)有( 12 )组.
︱y+z︳2013+ ︳z+x︳2013 + ︳x+y︳2012 =2的整数解数组(x,y,z)有( )组.正确的应该是(y+z)^2013+(z+x)^2013 + (x+y+1)^2 =2的整数解数组(x,z)有( )组.希望有人能尽快解答,万谢!
若x+y=y+z=z+x=2013,则x+y+z=__________.
x-y/(z-x)(z-y) 一y-z/(x-y)(x-z) +z-x/(y-z)(y-x)
x^-(y-z)^/(x+y)^-z^
计算(x+y-z)(x-y-z)
计算:(x-y+z)(-x+y+z)
(x+y-z)(x-y+z)=
x y y ...y z x y ...y z z x ...y ........z z z ...x 求解行列式.
已知:方程组2012(x-y)+2013(y-z)+2014(z-x)=02012²(x-y)+2013²(y-z)+2014²(z-x)=2013,求z-y的值?
已知2012(x-y)+2013(y-z)+2014(z-x)=0 2012^2(x-y)+2013^3(y-z)+2014^(z-x)=2013 求x-z的值^表示乘方
z变换X(z)=1+z^2013-z^-2013,求x(2013)
x+y>z 0
用乘法公式计算(x+y)(x-y)+(-y-z)(-y+z)+(-x+z)(z+x)
计算:(X+y+z)(-x+y+z)(x-y+z)(x+y-z)
(x+y-z)(x-y+z)-(x+y+z)(x-y-z)
因式分解 :(x+y-z)(x-y-z)+(y-x+z)(y-x-z)
因式分解测试题x(x+y-z)+y(x+y-z)+z(z-x-y)
(x+y+z)(-x+y+z)(x-y+z)(x+y-z)等于什么?