Exercise 1.Consider the following system of linear equations where a is a number:2x + 3y - z = a-4x - 6y = a-x- z = a注:这仨是个方程组 大括号打不进来a) For what values of a does the system above have a unique solution?b) For what val
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![Exercise 1.Consider the following system of linear equations where a is a number:2x + 3y - z = a-4x - 6y = a-x- z = a注:这仨是个方程组 大括号打不进来a) For what values of a does the system above have a unique solution?b) For what val](/uploads/image/z/10366311-39-1.jpg?t=Exercise+1.Consider+the+following+system+of+linear+equations+where+a+is+a+number%3A2x+%2B+3y+-+z+%3D+a-4x+-+6y+%3D+a-x-+z+%3D+a%E6%B3%A8%EF%BC%9A%E8%BF%99%E4%BB%A8%E6%98%AF%E4%B8%AA%E6%96%B9%E7%A8%8B%E7%BB%84+%E5%A4%A7%E6%8B%AC%E5%8F%B7%E6%89%93%E4%B8%8D%E8%BF%9B%E6%9D%A5a%29+For+what+values+of+a+does+the+system+above+have+a+unique+solution%3Fb%29+For+what+val)
Exercise 1.Consider the following system of linear equations where a is a number:2x + 3y - z = a-4x - 6y = a-x- z = a注:这仨是个方程组 大括号打不进来a) For what values of a does the system above have a unique solution?b) For what val
Exercise 1.Consider the following system of linear equations where a is a number:
2x + 3y - z = a
-4x - 6y = a
-x- z = a
注:这仨是个方程组 大括号打不进来
a) For what values of a does the system above have a unique solution?
b) For what values of a the system above does not have a solution?
c) What is the solution to the system above if a =
d) What is the solution to the system above if a = 3/2?
Exercise 2 a) Solve the following maximization problem x; y \x15 0:
maxx,y u(x,y) =1/3lnx +2/3lny
s.t.3x + 2y = 24
注:方程组
b) Solve the following maximization problem for x; y \x15 0:
maxx,y u(x,y) = min{2x -y; 5x - 2y}
s.t.x + y = 5
注:方程组
where min{a,b} is the minimum number between a and b.Thus,for instance:min{5,4} =4,min{-2,-7} = -7,min{2x,4x} = 2x if x \x15大于等于0 and min{2x,4x} = 4x if x 小于等于\x14 0,etc.
不好意思 第一题 最后一个方程 弄错了 应该是 -x-z= a2 a的平方!
Exercise 1.Consider the following system of linear equations where a is a number:2x + 3y - z = a-4x - 6y = a-x- z = a注:这仨是个方程组 大括号打不进来a) For what values of a does the system above have a unique solution?b) For what val
x=1/2a.y=-1/2a,z=-2/3a,在分析a的值就行了啊
能不能问一下你用的这本英文版高中数学课本的具体信息吗?具体名称、出版社,编者等能不能跟我说一下呢?
先求方程的解x=-a的平方+3a,y=2/3a的平方-13/6a,z=-3a.先求前两个,三角形>0,有两个不等实数根,求出三角形=零,就只有一个实数根,就求出唯一的解了。第二小道题正好三角形>0就行了。我找不到三角形那个符号,希望您能理解不好意思 第一题 最后一个方程 弄错了 应该是 -x-z= a2 a的平方! 所以X不等于-a的 您会第二题么。。。...
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先求方程的解x=-a的平方+3a,y=2/3a的平方-13/6a,z=-3a.先求前两个,三角形>0,有两个不等实数根,求出三角形=零,就只有一个实数根,就求出唯一的解了。第二小道题正好三角形>0就行了。我找不到三角形那个符号,希望您能理解
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you can use Lagrange multiplier to solve 2, 3. 1 is easy.
你告诉我maxx,y u(x, y)什么意思我绝对可以帮你解出来
第一题任何时候都有唯一解
我英语看这个有点蛋疼