化简求解,已知x=三分之一,求6x²-(2x-1)(3x-2)+(x+3)(x-2)
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/27 05:10:30
![化简求解,已知x=三分之一,求6x²-(2x-1)(3x-2)+(x+3)(x-2)](/uploads/image/z/995512-40-2.jpg?t=%E5%8C%96%E7%AE%80%E6%B1%82%E8%A7%A3%2C%E5%B7%B2%E7%9F%A5x%3D%E4%B8%89%E5%88%86%E4%B9%8B%E4%B8%80%2C%E6%B1%826x%26%23178%3B-%282x-1%29%283x-2%29%2B%28x%2B3%29%28x-2%29)
化简求解,已知x=三分之一,求6x²-(2x-1)(3x-2)+(x+3)(x-2)
化简求解,已知x=三分之一,求6x²-(2x-1)(3x-2)+(x+3)(x-2)
化简求解,已知x=三分之一,求6x²-(2x-1)(3x-2)+(x+3)(x-2)
6x²-(2x-1)(3x-2)+(x+3)(x-2)
=x²+8x-8
= - 47 / 9