(1+k^2)(100-80k^2-100k^4)/(4+5k^2)^2=1280/81 k是多少?
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![(1+k^2)(100-80k^2-100k^4)/(4+5k^2)^2=1280/81 k是多少?](/uploads/image/z/9848259-27-9.jpg?t=%EF%BC%881%2Bk%5E2%29%28100-80k%5E2-100k%5E4%29%2F%284%2B5k%5E2%29%5E2%3D1280%2F81+k%E6%98%AF%E5%A4%9A%E5%B0%91%3F)
(1+k^2)(100-80k^2-100k^4)/(4+5k^2)^2=1280/81 k是多少?
(1+k^2)(100-80k^2-100k^4)/(4+5k^2)^2=1280/81 k是多少?
(1+k^2)(100-80k^2-100k^4)/(4+5k^2)^2=1280/81 k是多少?
(1+k^2)(100-80k^2-100k^4)/(4+5k^2)^2=1280/81
5-4k^2-5k^4=64/81*(4+5k^2)^2/(1+k^2)
k^2>=0
所以,5-4k^2-5k^4的最大值是5
64/81*(4+5k^2)^2/(1+k^2)
=64/81*16*(1+5/4k^2)^2/(1+k^2)
>64*16/81=1024/81>5
所以不存在这样的k,使得原方程有解.
即原方程无解.
太复杂了