a大于0,b大于0.证明(1/a+1/b)分之2小于等于跟号ab小于等于a+b/2小于等于跟号a^2+b^2/2
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/27 12:21:03
![a大于0,b大于0.证明(1/a+1/b)分之2小于等于跟号ab小于等于a+b/2小于等于跟号a^2+b^2/2](/uploads/image/z/972377-17-7.jpg?t=a%E5%A4%A7%E4%BA%8E0%2Cb%E5%A4%A7%E4%BA%8E0.%E8%AF%81%E6%98%8E%EF%BC%881%2Fa%2B1%2Fb%EF%BC%89%E5%88%86%E4%B9%8B2%E5%B0%8F%E4%BA%8E%E7%AD%89%E4%BA%8E%E8%B7%9F%E5%8F%B7ab%E5%B0%8F%E4%BA%8E%E7%AD%89%E4%BA%8Ea%2Bb%2F2%E5%B0%8F%E4%BA%8E%E7%AD%89%E4%BA%8E%E8%B7%9F%E5%8F%B7a%5E2%2Bb%5E2%2F2)
a大于0,b大于0.证明(1/a+1/b)分之2小于等于跟号ab小于等于a+b/2小于等于跟号a^2+b^2/2
a大于0,b大于0.证明(1/a+1/b)分之2小于等于跟号ab小于等于a+b/2小于等于跟号a^2+b^2/2
a大于0,b大于0.证明(1/a+1/b)分之2小于等于跟号ab小于等于a+b/2小于等于跟号a^2+b^2/2
(a-b)²>=0 得a²+b²>=2ab 所以:a²+b²/2>=ab 根号a²+b²/2>=根号ab
(a+b)/2>=根号ab
(1/a+1/b)分之2=2ab/a+b