用换元法解分式方程6/x²+2x-3 - 18/x²+2x+1 = 06/x²+2x-3 - 18/x²+2x+1 = 0
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![用换元法解分式方程6/x²+2x-3 - 18/x²+2x+1 = 06/x²+2x-3 - 18/x²+2x+1 = 0](/uploads/image/z/961381-37-1.jpg?t=%E7%94%A8%E6%8D%A2%E5%85%83%E6%B3%95%E8%A7%A3%E5%88%86%E5%BC%8F%E6%96%B9%E7%A8%8B6%2Fx%26%23178%3B%2B2x-3+-+18%2Fx%26%23178%3B%2B2x%2B1+%3D+06%2Fx%26%23178%3B%2B2x-3++-+18%2Fx%26%23178%3B%2B2x%2B1+%3D+0)
用换元法解分式方程6/x²+2x-3 - 18/x²+2x+1 = 06/x²+2x-3 - 18/x²+2x+1 = 0
用换元法解分式方程6/x²+2x-3 - 18/x²+2x+1 = 0
6/x²+2x-3 - 18/x²+2x+1 = 0
用换元法解分式方程6/x²+2x-3 - 18/x²+2x+1 = 06/x²+2x-3 - 18/x²+2x+1 = 0
令x²+2x-1=y
则原方程为1/(y-2)-3/(y+2)=0
y+2-3y+6=0
-2y+8=0
y=4
∴x²+2x-1=4
x²+2x-5=0
(x+1)²=6
x+1=±√6
x=-1±√6