2-2^2-2^3-2^4-2^5-2^6-2^7-2^8-2^9.-2^20要不跳步的过程还有这道2-2^2-2^3-2^4-2^5-2^6-2^7-2^8-2^9......+2^20
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![2-2^2-2^3-2^4-2^5-2^6-2^7-2^8-2^9.-2^20要不跳步的过程还有这道2-2^2-2^3-2^4-2^5-2^6-2^7-2^8-2^9......+2^20](/uploads/image/z/960606-54-6.jpg?t=2-2%5E2-2%5E3-2%5E4-2%5E5-2%5E6-2%5E7-2%5E8-2%5E9.-2%5E20%E8%A6%81%E4%B8%8D%E8%B7%B3%E6%AD%A5%E7%9A%84%E8%BF%87%E7%A8%8B%E8%BF%98%E6%9C%89%E8%BF%99%E9%81%932-2%5E2-2%5E3-2%5E4-2%5E5-2%5E6-2%5E7-2%5E8-2%5E9......%2B2%5E20)
2-2^2-2^3-2^4-2^5-2^6-2^7-2^8-2^9.-2^20要不跳步的过程还有这道2-2^2-2^3-2^4-2^5-2^6-2^7-2^8-2^9......+2^20
2-2^2-2^3-2^4-2^5-2^6-2^7-2^8-2^9.-2^20
要不跳步的过程
还有这道2-2^2-2^3-2^4-2^5-2^6-2^7-2^8-2^9......+2^20
2-2^2-2^3-2^4-2^5-2^6-2^7-2^8-2^9.-2^20要不跳步的过程还有这道2-2^2-2^3-2^4-2^5-2^6-2^7-2^8-2^9......+2^20
以2^2为第一项,n=19,q=2,A1=4
2-Sn=2-[(A1q^n)/(q-1)-A1/(q-1)]
=2-[(4*2^19)/1-4/1]
=2-2^21+4
=6-2^21=6-2097152=-2097146
以2^2为第一项,n=18,q=2,A1=4
2-Sn+2^20=2-[(A1q^n)/(q-1)-A1/(q-1)]+2^20
=2-[4*2^18/1-4/1]+2^20
=2-2^20+4+2^20
=6
不知道对不对-,- 很久没沾数学了
123
以2^2为第一项,n=19,q=2,A1=4
2-Sn=2-[(A1q^n)/(q-1)-A1/(q-1)]
=2-[(4*2^19)/1-4/1]
=2-2^21+4
=6-2^21=6-2097152=-2097146
以2^2为第一项,n=18,q=2,A1=4
2-Sn+2^20=2-[(A1q^n)/(q-1)-A1/(q-1)]+2^20
=2-[4*2^18/1-4/1]+2^20
=2-2^20+4+2^20
=6