用分解因式法解下列方程:(1)( x+2)²=2x+4( 2) (x-2)²=4(x+1)²(3) 3(²-1)=(x-1)²(4) x²-2x-35=0(5) x²-7x+10=0
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![用分解因式法解下列方程:(1)( x+2)²=2x+4( 2) (x-2)²=4(x+1)²(3) 3(²-1)=(x-1)²(4) x²-2x-35=0(5) x²-7x+10=0](/uploads/image/z/9478020-12-0.jpg?t=%E7%94%A8%E5%88%86%E8%A7%A3%E5%9B%A0%E5%BC%8F%E6%B3%95%E8%A7%A3%E4%B8%8B%E5%88%97%E6%96%B9%E7%A8%8B%EF%BC%9A%EF%BC%881%EF%BC%89%EF%BC%88+x%2B2%EF%BC%89%26%23178%3B%3D2x%2B4%EF%BC%88+2%EF%BC%89+%EF%BC%88x-2%EF%BC%89%26%23178%3B%3D4%EF%BC%88x%2B1%EF%BC%89%26%23178%3B%EF%BC%883%EF%BC%89+3%EF%BC%88%26%23178%3B-1%EF%BC%89%3D%EF%BC%88x-1%29%26%23178%3B%EF%BC%884%EF%BC%89+x%26%23178%3B-2x-35%3D0%EF%BC%885%EF%BC%89+x%26%23178%3B-7x%2B10%3D0)
用分解因式法解下列方程:(1)( x+2)²=2x+4( 2) (x-2)²=4(x+1)²(3) 3(²-1)=(x-1)²(4) x²-2x-35=0(5) x²-7x+10=0
用分解因式法解下列方程:
(1)( x+2)²=2x+4
( 2) (x-2)²=4(x+1)²
(3) 3(²-1)=(x-1)²
(4) x²-2x-35=0
(5) x²-7x+10=0
用分解因式法解下列方程:(1)( x+2)²=2x+4( 2) (x-2)²=4(x+1)²(3) 3(²-1)=(x-1)²(4) x²-2x-35=0(5) x²-7x+10=0
(1)(x+2)²=2x+4
x²+4x+4=2x+4
x²+2x=0
x(x+2)=0
x=0或x=-2
(2)(x-2)²=4(x+1)²
x²-4x+4=4x²+8x+4
3x²+12x=0
x²+4x=0
x(x+4)=0
x=0或x=-4
(3) 3(x²-1)=(x-1)²
3x²-3=x²-2x+1
2x²+2x²-4=0
x²+x-2=0
(x+2)(X-1)=0
X=-2或x=1
(4)x²-2x-35=0
(x-7)(x+5)=0
x=7或x=-5
(5)x²-7x+10=0
(x-5)(x-2)=0
x=5或x=2
1)( x+2)²=2x+4
(x+2)(x+2-x-2)=0
x=-2,x=0
( 2) (x-2)²=4(x+1)²
(x-2+2x+2)(x-2-2x-2)=0
x=0,x=-4
(3) 3(x²-1)=(x-1)²
(x-1)(3x+3-x+1)=0
x=1...
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1)( x+2)²=2x+4
(x+2)(x+2-x-2)=0
x=-2,x=0
( 2) (x-2)²=4(x+1)²
(x-2+2x+2)(x-2-2x-2)=0
x=0,x=-4
(3) 3(x²-1)=(x-1)²
(x-1)(3x+3-x+1)=0
x=1,x=-2
(4) x²-2x-35=0
(x+5)(x-7)=0
x=-5,x=7
(5) x²-7x+10=0
(x-2)(x-5)=0
x=2,x=5
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