cos2x-sin2x =√2cos(2x+π/4) 是怎么来的?
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![cos2x-sin2x =√2cos(2x+π/4) 是怎么来的?](/uploads/image/z/9299194-34-4.jpg?t=cos2x-sin2x+%3D%E2%88%9A2cos%282x%2B%CF%80%2F4%29+%E6%98%AF%E6%80%8E%E4%B9%88%E6%9D%A5%E7%9A%84%3F)
cos2x-sin2x =√2cos(2x+π/4) 是怎么来的?
cos2x-sin2x =√2cos(2x+π/4) 是怎么来的?
cos2x-sin2x =√2cos(2x+π/4) 是怎么来的?
cos2x-sin2x
=√2(√2/2cos2x-√2/2sin2x )
=√2(cosπ/4cos2x-sinπ/4sin2x)
=√2cos(2x+π/4)