解不等式:(1+x)/2≤(2x-1)/3+1“/”为分数线[(1+x)/2]≤[(2x-1)/3]+1
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/05 01:27:39
![解不等式:(1+x)/2≤(2x-1)/3+1“/”为分数线[(1+x)/2]≤[(2x-1)/3]+1](/uploads/image/z/9296828-44-8.jpg?t=%E8%A7%A3%E4%B8%8D%E7%AD%89%E5%BC%8F%3A%281%2Bx%29%2F2%E2%89%A4%282x-1%29%2F3%2B1%E2%80%9C%2F%E2%80%9D%E4%B8%BA%E5%88%86%E6%95%B0%E7%BA%BF%5B%281%2Bx%29%2F2%5D%E2%89%A4%5B%282x-1%29%2F3%5D%2B1)
解不等式:(1+x)/2≤(2x-1)/3+1“/”为分数线[(1+x)/2]≤[(2x-1)/3]+1
解不等式:(1+x)/2≤(2x-1)/3+1
“/”为分数线
[(1+x)/2]≤[(2x-1)/3]+1
解不等式:(1+x)/2≤(2x-1)/3+1“/”为分数线[(1+x)/2]≤[(2x-1)/3]+1
[(1+x)/2]≤[(2x-1)/3]+1
==>3(x+1)≤2(2x-1)+6
==> 3x+3≤4x-2+6
==> 5-6≤4x-3x
==> -1≤x
不等式的为:{x| -1≤x}