(0.5x+0.5) + [0.5(0.5x+0.5)+0.5] + {0.5[0.5(0.5x+0.5)+0.5]+0.5} + ...+ = x等号前面总共有7个式子相加 都是一样的规律..
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/03 11:57:58
![(0.5x+0.5) + [0.5(0.5x+0.5)+0.5] + {0.5[0.5(0.5x+0.5)+0.5]+0.5} + ...+ = x等号前面总共有7个式子相加 都是一样的规律..](/uploads/image/z/8897304-48-4.jpg?t=%280.5x%2B0.5%29+%2B+%5B0.5%280.5x%2B0.5%29%2B0.5%5D+%2B+%7B0.5%5B0.5%280.5x%2B0.5%29%2B0.5%5D%2B0.5%7D+%2B+...%2B+%3D+x%E7%AD%89%E5%8F%B7%E5%89%8D%E9%9D%A2%E6%80%BB%E5%85%B1%E6%9C%897%E4%B8%AA%E5%BC%8F%E5%AD%90%E7%9B%B8%E5%8A%A0+%E9%83%BD%E6%98%AF%E4%B8%80%E6%A0%B7%E7%9A%84%E8%A7%84%E5%BE%8B..)
(0.5x+0.5) + [0.5(0.5x+0.5)+0.5] + {0.5[0.5(0.5x+0.5)+0.5]+0.5} + ...+ = x等号前面总共有7个式子相加 都是一样的规律..
(0.5x+0.5) + [0.5(0.5x+0.5)+0.5] + {0.5[0.5(0.5x+0.5)+0.5]+0.5} + ...+ = x
等号前面总共有7个式子相加 都是一样的规律..
(0.5x+0.5) + [0.5(0.5x+0.5)+0.5] + {0.5[0.5(0.5x+0.5)+0.5]+0.5} + ...+ = x等号前面总共有7个式子相加 都是一样的规律..
第三个式子中,[]里面是不是多加了一个0.5?
如果去掉那个0.5
左边可以分两部分求和
第一部分是A1=(0.5x+0.5)为首项
Q=0.5为公比的等比数列的前6项和
S6=A1*(1-Q的6次方)/(1-Q)
再加上第二部分 6个0.5就可以了