int x=5; int y=2+(x+=x++,x+8,++x); printf("%d",y); 结果是多少,为什么?请大侠们解释清楚点,
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/30 05:20:20
![int x=5; int y=2+(x+=x++,x+8,++x); printf(](/uploads/image/z/8848139-59-9.jpg?t=int+x%3D5%3B+int+y%3D2%2B%28x%2B%3Dx%2B%2B%2Cx%2B8%2C%2B%2Bx%29%3B+printf%28%22%25d%22%2Cy%29%3B+%E7%BB%93%E6%9E%9C%E6%98%AF%E5%A4%9A%E5%B0%91%2C%E4%B8%BA%E4%BB%80%E4%B9%88%3F%E8%AF%B7%E5%A4%A7%E4%BE%A0%E4%BB%AC%E8%A7%A3%E9%87%8A%E6%B8%85%E6%A5%9A%E7%82%B9%2C)
int x=5; int y=2+(x+=x++,x+8,++x); printf("%d",y); 结果是多少,为什么?请大侠们解释清楚点,
int x=5; int y=2+(x+=x++,x+8,++x); printf("%d",y); 结果是多少,为什么?请大侠们解释清楚点,
int x=5; int y=2+(x+=x++,x+8,++x); printf("%d",y); 结果是多少,为什么?请大侠们解释清楚点,
结果为14
y的值为括号内最左边的式子的值加上2; 括号内的计算顺序是从右向左.