设f'(x)在[a,b]上连续,且f(a)=0,│∫(a~b)f(x)dx│≤((b-a)^2)/2)max(a≤x≤b)│f'(x)│
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![设f'(x)在[a,b]上连续,且f(a)=0,│∫(a~b)f(x)dx│≤((b-a)^2)/2)max(a≤x≤b)│f'(x)│](/uploads/image/z/8754745-49-5.jpg?t=%E8%AE%BEf%27%28x%29%E5%9C%A8%5Ba%2Cb%5D%E4%B8%8A%E8%BF%9E%E7%BB%AD%2C%E4%B8%94f%28a%29%3D0%2C%E2%94%82%E2%88%AB%28a%EF%BD%9Eb%29f%28x%29dx%E2%94%82%E2%89%A4%28%28b-a%29%5E2%29%2F2%29max%28a%E2%89%A4x%E2%89%A4b%29%E2%94%82f%27%28x%29%E2%94%82)
设f'(x)在[a,b]上连续,且f(a)=0,│∫(a~b)f(x)dx│≤((b-a)^2)/2)max(a≤x≤b)│f'(x)│
设f'(x)在[a,b]上连续,且f(a)=0,│∫(a~b)f(x)dx│≤((b-a)^2)/2)max(a≤x≤b)│f'(x)│
设f'(x)在[a,b]上连续,且f(a)=0,│∫(a~b)f(x)dx│≤((b-a)^2)/2)max(a≤x≤b)│f'(x)│
f(x)-f(a)=f'(c)(x-a) |∫f(x)dx|=|∫f'(c)(x-a)dx=(b-a)^2/2*|f'(c)|
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