如图所示,点D.E在△ABC的边BC上,AB=AC,AD=AE,BD=CE.求证:△ABE≌△ACD
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/04 11:44:12
![如图所示,点D.E在△ABC的边BC上,AB=AC,AD=AE,BD=CE.求证:△ABE≌△ACD](/uploads/image/z/8698694-14-4.jpg?t=%E5%A6%82%E5%9B%BE%E6%89%80%E7%A4%BA%2C%E7%82%B9D.E%E5%9C%A8%E2%96%B3ABC%E7%9A%84%E8%BE%B9BC%E4%B8%8A%2CAB%3DAC%2CAD%3DAE%2CBD%3DCE.%E6%B1%82%E8%AF%81%EF%BC%9A%E2%96%B3ABE%E2%89%8C%E2%96%B3ACD)
如图所示,点D.E在△ABC的边BC上,AB=AC,AD=AE,BD=CE.求证:△ABE≌△ACD
如图所示,点D.E在△ABC的边BC上,AB=AC,AD=AE,BD=CE.求证:△ABE≌△ACD
如图所示,点D.E在△ABC的边BC上,AB=AC,AD=AE,BD=CE.求证:△ABE≌△ACD
∵AB=AC
∴△ABC为等腰三角形
∴∠B=∠C
∵BD=CE
DE=ED
∴BD+DE=CE+ED 即BE=CD
∴△ABE≌△ACD
因为AB=AC 所以角B=角C 又因为AD=AE 所以角ADE=角AED 所以角ADB=角AEC 所以角BAD=角CAE AB=AC❶ 角BAD=角CAE❷ AD=AE❸(SAS)
无法不vsfvg