设f(x)在【0,1】上连续,在(0,1)内可导,且f(0)=f(1)=0,f(1/2)=1/2,证明,存在ξ∈(0,1),使得f'(ξ)=1/3
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![设f(x)在【0,1】上连续,在(0,1)内可导,且f(0)=f(1)=0,f(1/2)=1/2,证明,存在ξ∈(0,1),使得f'(ξ)=1/3](/uploads/image/z/8668818-18-8.jpg?t=%E8%AE%BEf%28x%29%E5%9C%A8%E3%80%900%2C1%E3%80%91%E4%B8%8A%E8%BF%9E%E7%BB%AD%2C%E5%9C%A8%280%2C1%29%E5%86%85%E5%8F%AF%E5%AF%BC%2C%E4%B8%94f%280%29%3Df%281%29%3D0%2Cf%281%2F2%29%3D1%2F2%2C%E8%AF%81%E6%98%8E%2C%E5%AD%98%E5%9C%A8%CE%BE%E2%88%88%280%2C1%29%2C%E4%BD%BF%E5%BE%97f%27%EF%BC%88%CE%BE%EF%BC%89%3D1%2F3)
设f(x)在【0,1】上连续,在(0,1)内可导,且f(0)=f(1)=0,f(1/2)=1/2,证明,存在ξ∈(0,1),使得f'(ξ)=1/3
设f(x)在【0,1】上连续,在(0,1)内可导,且f(0)=f(1)=0,f(1/2)=1/2,证明,存在ξ∈(0,1),使得f'(ξ)=1/3
设f(x)在【0,1】上连续,在(0,1)内可导,且f(0)=f(1)=0,f(1/2)=1/2,证明,存在ξ∈(0,1),使得f'(ξ)=1/3
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