已知x^2+√2y=√3,y^2+√2x=√3,且x≠y,求x+y的值
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![已知x^2+√2y=√3,y^2+√2x=√3,且x≠y,求x+y的值](/uploads/image/z/8622581-5-1.jpg?t=%E5%B7%B2%E7%9F%A5x%5E2%2B%E2%88%9A2y%3D%E2%88%9A3%2Cy%5E2%2B%E2%88%9A2x%3D%E2%88%9A3%2C%E4%B8%94x%E2%89%A0y%2C%E6%B1%82x%2By%E7%9A%84%E5%80%BC)
已知x^2+√2y=√3,y^2+√2x=√3,且x≠y,求x+y的值
已知x^2+√2y=√3,y^2+√2x=√3,且x≠y,求x+y的值
已知x^2+√2y=√3,y^2+√2x=√3,且x≠y,求x+y的值
x²+√2y=√3
y²+√2x=√3
x²-y²+√2(y-x)=0
(x+y)(x-y)-√2(x-y)=0
(x-y)(x+y-√2)=0
因为x不等于y
所以x+y=√2