函数y=3cos((π/3)-2x)的递减区间是A.[kπ-(π/2),kπ+(5π/12)] (k∈z)B.[kπ+(5π/12),kπ+(11π/12)](k∈z)C.[kπ-(π/3),kπ+(π/6)](k∈z)D.[kπ+(π/6),kπ+(2π/3)](k∈z)
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/27 22:19:57
![函数y=3cos((π/3)-2x)的递减区间是A.[kπ-(π/2),kπ+(5π/12)] (k∈z)B.[kπ+(5π/12),kπ+(11π/12)](k∈z)C.[kπ-(π/3),kπ+(π/6)](k∈z)D.[kπ+(π/6),kπ+(2π/3)](k∈z)](/uploads/image/z/8612748-36-8.jpg?t=%E5%87%BD%E6%95%B0y%3D3cos%EF%BC%88%EF%BC%88%CF%80%2F3%EF%BC%89-2x%EF%BC%89%E7%9A%84%E9%80%92%E5%87%8F%E5%8C%BA%E9%97%B4%E6%98%AFA.%5Bk%CF%80-%EF%BC%88%CF%80%2F2%EF%BC%89%2Ck%CF%80%2B%EF%BC%885%CF%80%2F12%EF%BC%89%5D+%28k%E2%88%88z%29B.%5Bk%CF%80%2B%EF%BC%885%CF%80%2F12%EF%BC%89%2Ck%CF%80%2B%EF%BC%8811%CF%80%2F12%EF%BC%89%5D%EF%BC%88k%E2%88%88z%29C.%5Bk%CF%80-%EF%BC%88%CF%80%2F3%EF%BC%89%2Ck%CF%80%2B%EF%BC%88%CF%80%2F6%EF%BC%89%5D%EF%BC%88k%E2%88%88z%29D.%5Bk%CF%80%2B%EF%BC%88%CF%80%2F6%EF%BC%89%2Ck%CF%80%2B%EF%BC%882%CF%80%2F3%EF%BC%89%5D%EF%BC%88k%E2%88%88z%29)
函数y=3cos((π/3)-2x)的递减区间是A.[kπ-(π/2),kπ+(5π/12)] (k∈z)B.[kπ+(5π/12),kπ+(11π/12)](k∈z)C.[kπ-(π/3),kπ+(π/6)](k∈z)D.[kπ+(π/6),kπ+(2π/3)](k∈z)
函数y=3cos((π/3)-2x)的递减区间是
A.[kπ-(π/2),kπ+(5π/12)] (k∈z)
B.[kπ+(5π/12),kπ+(11π/12)](k∈z)
C.[kπ-(π/3),kπ+(π/6)](k∈z)
D.[kπ+(π/6),kπ+(2π/3)](k∈z)
函数y=3cos((π/3)-2x)的递减区间是A.[kπ-(π/2),kπ+(5π/12)] (k∈z)B.[kπ+(5π/12),kπ+(11π/12)](k∈z)C.[kπ-(π/3),kπ+(π/6)](k∈z)D.[kπ+(π/6),kπ+(2π/3)](k∈z)
选C啊
首先中括号里的代数式属于(0,π)闭区间,
然后解方程得.[-(π/3),+(π/6)]
因为周期kπ
所以选C