解一道分式方程,1/(x+5)+1/(x+8)=1/(x+6)+1/(x+7)做到(2x+13){(x+6)(x+7)-(x+5)(x+8)]=0的时候,为什么是2x+13=0,而不是(x+6)(x+7)-(x+5)(x+8)=0呢?
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/28 12:39:18
![解一道分式方程,1/(x+5)+1/(x+8)=1/(x+6)+1/(x+7)做到(2x+13){(x+6)(x+7)-(x+5)(x+8)]=0的时候,为什么是2x+13=0,而不是(x+6)(x+7)-(x+5)(x+8)=0呢?](/uploads/image/z/8597221-61-1.jpg?t=%E8%A7%A3%E4%B8%80%E9%81%93%E5%88%86%E5%BC%8F%E6%96%B9%E7%A8%8B%2C1%2F%EF%BC%88x%2B5%29%2B1%2F%28x%2B8%29%3D1%2F%28x%2B6%29%2B1%2F%28x%2B7%29%E5%81%9A%E5%88%B0%282x%2B13%29%7B%28x%2B6%29%28x%2B7%29-%28x%2B5%29%28x%2B8%29%5D%3D0%E7%9A%84%E6%97%B6%E5%80%99%EF%BC%8C%E4%B8%BA%E4%BB%80%E4%B9%88%E6%98%AF2x%2B13%3D0%EF%BC%8C%E8%80%8C%E4%B8%8D%E6%98%AF%28x%2B6%29%28x%2B7%29-%28x%2B5%29%28x%2B8%29%3D0%E5%91%A2%3F)
解一道分式方程,1/(x+5)+1/(x+8)=1/(x+6)+1/(x+7)做到(2x+13){(x+6)(x+7)-(x+5)(x+8)]=0的时候,为什么是2x+13=0,而不是(x+6)(x+7)-(x+5)(x+8)=0呢?
解一道分式方程,
1/(x+5)+1/(x+8)=1/(x+6)+1/(x+7)
做到(2x+13){(x+6)(x+7)-(x+5)(x+8)]=0的时候,为什么是2x+13=0,而不是(x+6)(x+7)-(x+5)(x+8)=0呢?
解一道分式方程,1/(x+5)+1/(x+8)=1/(x+6)+1/(x+7)做到(2x+13){(x+6)(x+7)-(x+5)(x+8)]=0的时候,为什么是2x+13=0,而不是(x+6)(x+7)-(x+5)(x+8)=0呢?
1/(x+5)+1/(x+8)=1/(x+6)+1/(x+7)
(x+6)(x+7)(x+8)+(x+6)(x+7)(x+5)=(x+5)(x+7)(x+8)+(x+5)(x+6)(x+8)
[(x+6)(x+7)]([x+8)+(x+5)]=[(x+5)(x+8)][(x+6)+(x+7)]
[(x+6)(x+7)](2x+13)=[(x+5)(x+8)](2x+13)
(2x+13){(x+6)(x+7)-(x+5)(x+8)]=0
2x+13=0
x=-13/2
1/(x+5)+1/(x+8)=1/(x+6)+1/(x+7)
(x+6)(x+7)(x+8)+(x+6)(x+7)(x+5)=(x+5)(x+7)(x+8)+(x+5)(x+6)(x+8)
[(x+6)(x+7)]([x+8)+(x+5)]=[(x+5)(x+8)][(x+6)+(x+7)]
[(x+6)(x+7)](2x+13)=[(x+5)(x+8)](2x+13)
(2x+13){(x+6)(x+7)-(x+5)(x+8)]=0
2x+13=0
x=-13/2
应该是对的