A(X1,Y1)B(X2,Y2)C(X3,Y3)求向量AB,BC,CA ,并验证向量AB+BC+CA=0是不是这样的,AB=-BC-CA=(X2-X1,Y2-Y1) BC=-CA-AB=(X3-X2,Y3-Y2) CA=-AB-BC=(X1-X3,Y1-Y3)接着是不是AB+BC+CA=(X2-X1,Y2-Y1)+(X3-X2,Y
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![A(X1,Y1)B(X2,Y2)C(X3,Y3)求向量AB,BC,CA ,并验证向量AB+BC+CA=0是不是这样的,AB=-BC-CA=(X2-X1,Y2-Y1) BC=-CA-AB=(X3-X2,Y3-Y2) CA=-AB-BC=(X1-X3,Y1-Y3)接着是不是AB+BC+CA=(X2-X1,Y2-Y1)+(X3-X2,Y](/uploads/image/z/8556717-21-7.jpg?t=A%28X1%2CY1%29B%28X2%2CY2%29C%28X3%2CY3%29%E6%B1%82%E5%90%91%E9%87%8FAB%2CBC%2CCA+%2C%E5%B9%B6%E9%AA%8C%E8%AF%81%E5%90%91%E9%87%8FAB%2BBC%2BCA%3D0%E6%98%AF%E4%B8%8D%E6%98%AF%E8%BF%99%E6%A0%B7%E7%9A%84%2CAB%3D-BC-CA%3D%28X2-X1%2CY2-Y1%29++++++++++++++++++++++++BC%3D-CA-AB%3D%28X3-X2%2CY3-Y2%29++++++++++++++++++++++++CA%3D-AB-BC%3D%28X1-X3%2CY1-Y3%29%E6%8E%A5%E7%9D%80%E6%98%AF%E4%B8%8D%E6%98%AFAB%2BBC%2BCA%3D%28X2-X1%2CY2-Y1%29%2B%28X3-X2%2CY)
A(X1,Y1)B(X2,Y2)C(X3,Y3)求向量AB,BC,CA ,并验证向量AB+BC+CA=0是不是这样的,AB=-BC-CA=(X2-X1,Y2-Y1) BC=-CA-AB=(X3-X2,Y3-Y2) CA=-AB-BC=(X1-X3,Y1-Y3)接着是不是AB+BC+CA=(X2-X1,Y2-Y1)+(X3-X2,Y
A(X1,Y1)B(X2,Y2)C(X3,Y3)求向量AB,BC,CA ,并验证向量AB+BC+CA=0
是不是这样的,AB=-BC-CA=(X2-X1,Y2-Y1) BC=-CA-AB=(X3-X2,Y3-Y2) CA=-AB-BC=(X1-X3,Y1-Y3)接着是不是AB+BC+CA=(X2-X1,Y2-Y1)+(X3-X2,Y3-Y2)+(X1-X3,Y1-Y3) =(X2-X1+X3-X2+X1-X3,Y2-Y1+Y3-Y2+Y1-Y3) =(0,0) 是不是这样的?
A(X1,Y1)B(X2,Y2)C(X3,Y3)求向量AB,BC,CA ,并验证向量AB+BC+CA=0是不是这样的,AB=-BC-CA=(X2-X1,Y2-Y1) BC=-CA-AB=(X3-X2,Y3-Y2) CA=-AB-BC=(X1-X3,Y1-Y3)接着是不是AB+BC+CA=(X2-X1,Y2-Y1)+(X3-X2,Y
你的方法过于繁琐
向量AB=向量OB-向量OA=(x2-x1,y2-y1)
向量BC=向量OC-向量OB=(x3-x2,y3-y2)
向量CA=向量OA-向量OC=(x1-x3,y1-y3)
所以 向量AB+向量BC+向量CA=(0,0)=0向量