高等数学求偏导数这题怎么做: x z=ln tan----- y题目是z=ln tan x/y希望能把这道题的步骤给我看
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![高等数学求偏导数这题怎么做: x z=ln tan----- y题目是z=ln tan x/y希望能把这道题的步骤给我看](/uploads/image/z/8517026-2-6.jpg?t=%E9%AB%98%E7%AD%89%E6%95%B0%E5%AD%A6%E6%B1%82%E5%81%8F%E5%AF%BC%E6%95%B0%E8%BF%99%E9%A2%98%E6%80%8E%E4%B9%88%E5%81%9A%EF%BC%9A+x+z%3Dln+tan-----+y%E9%A2%98%E7%9B%AE%E6%98%AFz%3Dln+tan++x%2Fy%E5%B8%8C%E6%9C%9B%E8%83%BD%E6%8A%8A%E8%BF%99%E9%81%93%E9%A2%98%E7%9A%84%E6%AD%A5%E9%AA%A4%E7%BB%99%E6%88%91%E7%9C%8B)
高等数学求偏导数这题怎么做: x z=ln tan----- y题目是z=ln tan x/y希望能把这道题的步骤给我看
高等数学求偏导数这题怎么做: x z=ln tan----- y
题目是z=ln tan x/y
希望能把这道题的步骤给我看
高等数学求偏导数这题怎么做: x z=ln tan----- y题目是z=ln tan x/y希望能把这道题的步骤给我看
dz =[1/tan(x/y)]*sec^2(x/y) *[dx/y + (-x/y^2)dy]
dz/dx = 2 /[y *sin(2x/y)]
dz/dy= - 2x/[y^2*sin(2x/y)]
dz/dx =d (ln tan x/y)/dx
=(1/tan( x/y)) *d (tan x/y)/dx
=(1/tan( x/y)) *sec^2( x/y)*d(x/y)
=(1/tan( x/y)) *sec^2( x/y)*dx/y
=2 /[y *sin(2x/y)]
dz/dy =d (ln tan x/y)/dy
=(1/tan( x/y)) *d (tan x/y)/dy
=(1/tan( x/y)) *sec^2( x/y)*d(x/y)
=(1/tan( x/y)) *sec^2( x/y)*(-x/y^2)
= - 2x/[y^2*sin(2x/y)]