> u=xlsread('D:\1.xls',1,'A1:A279');v=xlsread('D:\1.xls',1,'B1:B279');X=[ones(279,1),v',u',(u.*v)',(v.^2)'];%1与自变量组成的矩阵[b,bint,r,rint,s]=regress(-(v.^2)',X);b,bint,s
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/29 22:08:37
![> u=xlsread('D:\1.xls',1,'A1:A279');v=xlsread('D:\1.xls',1,'B1:B279');X=[ones(279,1),v',u',(u.*v)',(v.^2)'];%1与自变量组成的矩阵[b,bint,r,rint,s]=regress(-(v.^2)',X);b,bint,s](/uploads/image/z/8475405-69-5.jpg?t=%3E+u%3Dxlsread%28%27D%3A%5C1.xls%27%2C1%2C%27A1%3AA279%27%29%3Bv%3Dxlsread%28%27D%3A%5C1.xls%27%2C1%2C%27B1%3AB279%27%29%3BX%3D%5Bones%28279%2C1%29%2Cv%27%2Cu%27%2C%28u.%2Av%29%27%2C%28v.%5E2%29%27%5D%3B%251%E4%B8%8E%E8%87%AA%E5%8F%98%E9%87%8F%E7%BB%84%E6%88%90%E7%9A%84%E7%9F%A9%E9%98%B5%5Bb%2Cbint%2Cr%2Crint%2Cs%5D%3Dregress%28-%28v.%5E2%29%27%2CX%29%3Bb%2Cbint%2Cs)
> u=xlsread('D:\1.xls',1,'A1:A279');v=xlsread('D:\1.xls',1,'B1:B279');X=[ones(279,1),v',u',(u.*v)',(v.^2)'];%1与自变量组成的矩阵[b,bint,r,rint,s]=regress(-(v.^2)',X);b,bint,s
> u=xlsread('D:\1.xls',1,'A1:A279');
v=xlsread('D:\1.xls',1,'B1:B279');
X=[ones(279,1),v',u',(u.*v)',(v.^2)'];%1与自变量组成的矩阵
[b,bint,r,rint,s]=regress(-(v.^2)',X);
b,bint,s
> u=xlsread('D:\1.xls',1,'A1:A279');v=xlsread('D:\1.xls',1,'B1:B279');X=[ones(279,1),v',u',(u.*v)',(v.^2)'];%1与自变量组成的矩阵[b,bint,r,rint,s]=regress(-(v.^2)',X);b,bint,s
clc
clear
u=xlsread('D:\1.xls',1,'A1:A279');
v=xlsread('D:\1.xls',1,'B1:B279');
X=[ones(279,1),v,u,(u.*v),(v.^2)];%1与自变量组成的矩阵
[b,bint,r,rint,s]=regress(-(v.^2),X);
b,bint,s
u,v本来就是列向量了,不用转置.
X=[ones(279,1),v,u,(u.*v),(v.^2)];%中怎么也有v.^2这样子根本不用回归,一看就知系数为
0 0 0 0 -1运行结果也确实如此