(3x-2)²+y-3的绝对值=0,求5(2x-y)-2(6x-2y+2)+(4x-3y-½)的值
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![(3x-2)²+y-3的绝对值=0,求5(2x-y)-2(6x-2y+2)+(4x-3y-½)的值](/uploads/image/z/806069-29-9.jpg?t=%EF%BC%883x%EF%BC%8D2%EF%BC%89%26%23178%3B%EF%BC%8By-3%E7%9A%84%E7%BB%9D%E5%AF%B9%E5%80%BC%EF%BC%9D0%2C%E6%B1%825%EF%BC%882x-y%EF%BC%89-2%EF%BC%886x-2y%EF%BC%8B2%EF%BC%89%EF%BC%8B%EF%BC%884x%EF%BC%8D3y%EF%BC%8D%26%23189%3B%EF%BC%89%E7%9A%84%E5%80%BC)
(3x-2)²+y-3的绝对值=0,求5(2x-y)-2(6x-2y+2)+(4x-3y-½)的值
(3x-2)²+y-3的绝对值=0,求5(2x-y)-2(6x-2y+2)+(4x-3y-½)的值
(3x-2)²+y-3的绝对值=0,求5(2x-y)-2(6x-2y+2)+(4x-3y-½)的值
题意得
3x-2=0 y-3=0
∴x=2/3 y=3
∴原式=10x-5y-12x+4y-4+4x-3y-1/2
=2x-4y-4.5
=4/3-12-9/2
=-91/6