(1+ 2b²/a²-b²)÷(1+ 2b/a-b),其中3a+2b=0化简求值,{1+(2b²/a²-b²)}÷{1+(2b/a-b)},其中3a+2b=0
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![(1+ 2b²/a²-b²)÷(1+ 2b/a-b),其中3a+2b=0化简求值,{1+(2b²/a²-b²)}÷{1+(2b/a-b)},其中3a+2b=0](/uploads/image/z/765381-21-1.jpg?t=%281%2B+2b%26%23178%3B%2Fa%26%23178%3B-b%26%23178%3B%29%C3%B7%EF%BC%881%2B+2b%2Fa-b%EF%BC%89%2C%E5%85%B6%E4%B8%AD3a%2B2b%3D0%E5%8C%96%E7%AE%80%E6%B1%82%E5%80%BC%EF%BC%8C%7B1%2B%EF%BC%882b%26%23178%3B%2Fa%26%23178%3B-b%26%23178%3B%EF%BC%89%7D%C3%B7%7B1%2B%EF%BC%882b%2Fa-b%EF%BC%89%7D%2C%E5%85%B6%E4%B8%AD3a%2B2b%3D0)
(1+ 2b²/a²-b²)÷(1+ 2b/a-b),其中3a+2b=0化简求值,{1+(2b²/a²-b²)}÷{1+(2b/a-b)},其中3a+2b=0
(1+ 2b²/a²-b²)÷(1+ 2b/a-b),其中3a+2b=0
化简求值,{1+(2b²/a²-b²)}÷{1+(2b/a-b)},其中3a+2b=0
(1+ 2b²/a²-b²)÷(1+ 2b/a-b),其中3a+2b=0化简求值,{1+(2b²/a²-b²)}÷{1+(2b/a-b)},其中3a+2b=0
3a+2b=0
∴b=-3a/2
原式=(a²-b²+2b²)/(a²-b²)÷(a-b+2b)/(a-b)
=(a²+b²)/(a+b)(a-b) ×(a-b)/(a+b)
=(a²+b²)/(a+b)²
=(a²+9a²/4)/(a-3a/2)²
=13
化成a/b的形式,后面a/b是知道的。或者将后面的a与b的关系带入消去一个字母