f(1)=1,f(2)=7,f(3)=19,f(4)=37······则f(n)=?老兄,你那个式子一个都不成立!
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/05 11:33:55
![f(1)=1,f(2)=7,f(3)=19,f(4)=37······则f(n)=?老兄,你那个式子一个都不成立!](/uploads/image/z/7615483-43-3.jpg?t=f%EF%BC%881%EF%BC%89%3D1%2Cf%EF%BC%882%EF%BC%89%3D7%2Cf%EF%BC%883%EF%BC%89%3D19%2Cf%EF%BC%884%EF%BC%89%3D37%C2%B7%C2%B7%C2%B7%C2%B7%C2%B7%C2%B7%E5%88%99f%EF%BC%88n%EF%BC%89%3D%3F%E8%80%81%E5%85%84%2C%E4%BD%A0%E9%82%A3%E4%B8%AA%E5%BC%8F%E5%AD%90%E4%B8%80%E4%B8%AA%E9%83%BD%E4%B8%8D%E6%88%90%E7%AB%8B%21)
f(1)=1,f(2)=7,f(3)=19,f(4)=37······则f(n)=?老兄,你那个式子一个都不成立!
f(1)=1,f(2)=7,f(3)=19,f(4)=37······则f(n)=?
老兄,你那个式子一个都不成立!
f(1)=1,f(2)=7,f(3)=19,f(4)=37······则f(n)=?老兄,你那个式子一个都不成立!
1*0+1
2*3+1
3*6+1
4*9+1
``······
所以f(n)=n*3(n-1)+1=3n方-3n+1