将一个多项式【(17x²-3x+4)-(ax²+bx+c)】除以(5x+6)后,得商式为(2x+1),余式为0,则a-b-c的值?
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![将一个多项式【(17x²-3x+4)-(ax²+bx+c)】除以(5x+6)后,得商式为(2x+1),余式为0,则a-b-c的值?](/uploads/image/z/759487-31-7.jpg?t=%E5%B0%86%E4%B8%80%E4%B8%AA%E5%A4%9A%E9%A1%B9%E5%BC%8F%E3%80%90%2817x%26%23178%3B-3x%2B4%29-%28ax%26%23178%3B%2Bbx%2Bc%29%E3%80%91%E9%99%A4%E4%BB%A5%285x%2B6%29%E5%90%8E%2C%E5%BE%97%E5%95%86%E5%BC%8F%E4%B8%BA%EF%BC%882x%EF%BC%8B1%EF%BC%89%2C%E4%BD%99%E5%BC%8F%E4%B8%BA0%2C%E5%88%99a%EF%BC%8Db%EF%BC%8Dc%E7%9A%84%E5%80%BC%3F)
将一个多项式【(17x²-3x+4)-(ax²+bx+c)】除以(5x+6)后,得商式为(2x+1),余式为0,则a-b-c的值?
将一个多项式【(17x²-3x+4)-(ax²+bx+c)】除以(5x+6)后,
得商式为(2x+1),余式为0,则a-b-c的值?
将一个多项式【(17x²-3x+4)-(ax²+bx+c)】除以(5x+6)后,得商式为(2x+1),余式为0,则a-b-c的值?
17x^2-3x+4-(2x+1)(5x+6)
=17x^2-3x+4-(10x^2+17x+6)
=17x^2-3x+4-10x^2-17x-6
=7x^2-20x-2
则,a=7,b=-20,c=-2
所以,a-b-c=7-(-20)-(-2)=29