已知(a-2)²+|b+1|=0,求(-a-b﹚²º¹²+2的8次方·﹙-1/a﹚的值
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![已知(a-2)²+|b+1|=0,求(-a-b﹚²º¹²+2的8次方·﹙-1/a﹚的值](/uploads/image/z/755624-56-4.jpg?t=%E5%B7%B2%E7%9F%A5%28a-2%EF%BC%89%26%23178%3B%2B%7Cb%2B1%7C%3D0%2C%E6%B1%82%28-a-b%EF%B9%9A%26%23178%3B%26%23186%3B%26%23185%3B%26%23178%3B%2B2%E7%9A%848%E6%AC%A1%E6%96%B9%C2%B7%EF%B9%99-1%2Fa%EF%B9%9A%E7%9A%84%E5%80%BC)
已知(a-2)²+|b+1|=0,求(-a-b﹚²º¹²+2的8次方·﹙-1/a﹚的值
已知(a-2)²+|b+1|=0,求(-a-b﹚²º¹²+2的8次方·﹙-1/a﹚的值
已知(a-2)²+|b+1|=0,求(-a-b﹚²º¹²+2的8次方·﹙-1/a﹚的值
解; 因为(a-2)²+|b+1|=0,
所以a-2=0,b+1=0
所以a=2,b=-1
(-a-b﹚²º¹²+2的8次方·﹙-1/a﹚
=(-2+1)²º¹²+2的8次方·﹙-1/2﹚
=1-2的7次方
=1-128
=-127
(a-2)²+|b+1|=0
a=2
b=-1
(-a-b﹚²º¹²+2的8次方·﹙-1/a﹚
=1-/128
=-127