设k∈R,x1,x2是方程x²-2kx+1-k²=0的两个实数根,求x1²+x2²的最小值?均值定理做!x1²+x2²=6k²-2=6k²-3+1≥3(2k²-1)≥1啥意思?
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![设k∈R,x1,x2是方程x²-2kx+1-k²=0的两个实数根,求x1²+x2²的最小值?均值定理做!x1²+x2²=6k²-2=6k²-3+1≥3(2k²-1)≥1啥意思?](/uploads/image/z/7109599-31-9.jpg?t=%E8%AE%BEk%E2%88%88R%2Cx1%2Cx2%E6%98%AF%E6%96%B9%E7%A8%8Bx%26%23178%3B-2kx%2B1-k%26%23178%3B%3D0%E7%9A%84%E4%B8%A4%E4%B8%AA%E5%AE%9E%E6%95%B0%E6%A0%B9%2C%E6%B1%82x1%26%23178%3B%2Bx2%26%23178%3B%E7%9A%84%E6%9C%80%E5%B0%8F%E5%80%BC%3F%E5%9D%87%E5%80%BC%E5%AE%9A%E7%90%86%E5%81%9A%21x1%26%23178%3B%2Bx2%26%23178%3B%3D6k%26%23178%3B-2%3D6k%26%23178%3B-3%2B1%E2%89%A53%282k%26%23178%3B-1%29%E2%89%A51%E5%95%A5%E6%84%8F%E6%80%9D%3F)
设k∈R,x1,x2是方程x²-2kx+1-k²=0的两个实数根,求x1²+x2²的最小值?均值定理做!x1²+x2²=6k²-2=6k²-3+1≥3(2k²-1)≥1啥意思?
设k∈R,x1,x2是方程x²-2kx+1-k²=0的两个实数根,求x1²+x2²的最小值?均值定理做!
x1²+x2²=6k²-2=6k²-3+1≥3(2k²-1)≥1啥意思?
设k∈R,x1,x2是方程x²-2kx+1-k²=0的两个实数根,求x1²+x2²的最小值?均值定理做!x1²+x2²=6k²-2=6k²-3+1≥3(2k²-1)≥1啥意思?