已知a(a-1)-(a²-b)=4,求½(a²+b²)-ab的值
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已知a(a-1)-(a²-b)=4,求½(a²+b²)-ab的值
已知a(a-1)-(a²-b)=4,求½(a²+b²)-ab的值
已知a(a-1)-(a²-b)=4,求½(a²+b²)-ab的值
由a(a-1)-(a²-b)=4可推出b-a=4
½(a²+b²)-ab=½(a-b)²=½*4²=8
8
a(a-1)-(a²-b)=4得b-a=4,½(a²+b²)-ab=1/2 (a-b)²=8