函数F(x)=x2+(a-1)x是偶函数,则函数g(x)=ax2-2x-1的单调递减区间是F(x)=x2+(a-1)x是偶函数是不是说明了a=1?
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![函数F(x)=x2+(a-1)x是偶函数,则函数g(x)=ax2-2x-1的单调递减区间是F(x)=x2+(a-1)x是偶函数是不是说明了a=1?](/uploads/image/z/639192-48-2.jpg?t=%E5%87%BD%E6%95%B0F%28x%29%3Dx2%2B%28a-1%29x%E6%98%AF%E5%81%B6%E5%87%BD%E6%95%B0%2C%E5%88%99%E5%87%BD%E6%95%B0g%28x%29%3Dax2-2x-1%E7%9A%84%E5%8D%95%E8%B0%83%E9%80%92%E5%87%8F%E5%8C%BA%E9%97%B4%E6%98%AFF%28x%29%3Dx2%2B%28a-1%29x%E6%98%AF%E5%81%B6%E5%87%BD%E6%95%B0%E6%98%AF%E4%B8%8D%E6%98%AF%E8%AF%B4%E6%98%8E%E4%BA%86a%3D1%3F)
函数F(x)=x2+(a-1)x是偶函数,则函数g(x)=ax2-2x-1的单调递减区间是F(x)=x2+(a-1)x是偶函数是不是说明了a=1?
函数F(x)=x2+(a-1)x是偶函数,则函数g(x)=ax2-2x-1的单调递减区间是
F(x)=x2+(a-1)x是偶函数是不是说明了a=1?
函数F(x)=x2+(a-1)x是偶函数,则函数g(x)=ax2-2x-1的单调递减区间是F(x)=x2+(a-1)x是偶函数是不是说明了a=1?
F(x)=x2+(a-1)x是偶函数
说明奇次项系数等于0
所以a-1=0
a=1
F(x)=x2+(a-1)x是偶函数
所以a-1=0
a=1g(x)=ax2-2x-1
=x2-2x-1
=(x-1)^2-2
所以单减区间是
x<1