十一.已知反应:Fe(s)+CO2(g)=FeO(s)+CO(g) 平衡常数K1 FeO(s)+H2(g)=Fe(s)+H2O(g) 平衡常数K2平衡常数K2T/K 973 1073 1173 1273 K1 1.47 1.81 2.15 2.48K2 0.420 0.500 0.600 0.670试计算在以上各温度时,下面反应:CO2(g)+H2(g)==
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![十一.已知反应:Fe(s)+CO2(g)=FeO(s)+CO(g) 平衡常数K1 FeO(s)+H2(g)=Fe(s)+H2O(g) 平衡常数K2平衡常数K2T/K 973 1073 1173 1273 K1 1.47 1.81 2.15 2.48K2 0.420 0.500 0.600 0.670试计算在以上各温度时,下面反应:CO2(g)+H2(g)==](/uploads/image/z/6391859-59-9.jpg?t=%E5%8D%81%E4%B8%80.%E5%B7%B2%E7%9F%A5%E5%8F%8D%E5%BA%94%EF%BC%9AFe%28s%29%2BCO2%28g%29%3DFeO%28s%29%2BCO%28g%29+%E5%B9%B3%E8%A1%A1%E5%B8%B8%E6%95%B0K1+FeO%28s%29%2BH2%28g%29%3DFe%28s%29%2BH2O%28g%29+%E5%B9%B3%E8%A1%A1%E5%B8%B8%E6%95%B0K2%E5%B9%B3%E8%A1%A1%E5%B8%B8%E6%95%B0K2T%2FK+973+1073+1173+1273+K1+1.47+1.81+2.15+2.48K2+0.420+0.500+0.600+0.670%E8%AF%95%E8%AE%A1%E7%AE%97%E5%9C%A8%E4%BB%A5%E4%B8%8A%E5%90%84%E6%B8%A9%E5%BA%A6%E6%97%B6%EF%BC%8C%E4%B8%8B%E9%9D%A2%E5%8F%8D%E5%BA%94%EF%BC%9ACO2%28g%29%2BH2%28g%29%3D%3D)
十一.已知反应:Fe(s)+CO2(g)=FeO(s)+CO(g) 平衡常数K1 FeO(s)+H2(g)=Fe(s)+H2O(g) 平衡常数K2平衡常数K2T/K 973 1073 1173 1273 K1 1.47 1.81 2.15 2.48K2 0.420 0.500 0.600 0.670试计算在以上各温度时,下面反应:CO2(g)+H2(g)==
十一.已知反应:Fe(s)+CO2(g)=FeO(s)+CO(g) 平衡常数K1 FeO(s)+H2(g)=Fe(s)+H2O(g) 平衡常数K2
平衡常数K2
T/K 973 1073 1173 1273
K1 1.47 1.81 2.15 2.48
K2 0.420 0.500 0.600 0.670
试计算在以上各温度时,下面反应:CO2(g)+H2(g)==CO2(g)+H2O(g)的平衡常数K,并根据计算结果判断此反应是吸热反应还是放热反应?
十一.已知反应:Fe(s)+CO2(g)=FeO(s)+CO(g) 平衡常数K1 FeO(s)+H2(g)=Fe(s)+H2O(g) 平衡常数K2平衡常数K2T/K 973 1073 1173 1273 K1 1.47 1.81 2.15 2.48K2 0.420 0.500 0.600 0.670试计算在以上各温度时,下面反应:CO2(g)+H2(g)==
升温K值增大反应吸热
升温K值减小反应放热
K1,K2都是吸热所以K反应是吸热反应
两式相加便得所求式,那么K=K1*K2,K1,K2根据定义式求出,然后算出各温度下的K,比较K是增大还是减小,当温升高时,若减小则是放热,否则是吸热.