已知函数f(x)=2sin^2x+2√3sinxcosx+a,x属于[π/4,π/2],且f(π/3)=4 1)求实数a的值 2)求函数f(x)的值已知函数f(x)=2sin^2x+2√3sinxcosx+a,x属于[π/4,π/2],且f(π/3)=4 1)求实数a的值 2)求函数f(x)的值域
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![已知函数f(x)=2sin^2x+2√3sinxcosx+a,x属于[π/4,π/2],且f(π/3)=4 1)求实数a的值 2)求函数f(x)的值已知函数f(x)=2sin^2x+2√3sinxcosx+a,x属于[π/4,π/2],且f(π/3)=4 1)求实数a的值 2)求函数f(x)的值域](/uploads/image/z/5919365-29-5.jpg?t=%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%28x%29%3D2sin%5E2x%2B2%E2%88%9A3sinxcosx%2Ba%2Cx%E5%B1%9E%E4%BA%8E%5B%CF%80%2F4%2C%CF%80%2F2%5D%2C%E4%B8%94f%28%CF%80%2F3%29%3D4+1%EF%BC%89%E6%B1%82%E5%AE%9E%E6%95%B0a%E7%9A%84%E5%80%BC+2%EF%BC%89%E6%B1%82%E5%87%BD%E6%95%B0f%EF%BC%88x%EF%BC%89%E7%9A%84%E5%80%BC%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%28x%29%3D2sin%5E2x%2B2%E2%88%9A3sinxcosx%2Ba%2Cx%E5%B1%9E%E4%BA%8E%5B%CF%80%2F4%2C%CF%80%2F2%5D%2C%E4%B8%94f%28%CF%80%2F3%29%3D4+1%EF%BC%89%E6%B1%82%E5%AE%9E%E6%95%B0a%E7%9A%84%E5%80%BC+2%EF%BC%89%E6%B1%82%E5%87%BD%E6%95%B0f%EF%BC%88x%EF%BC%89%E7%9A%84%E5%80%BC%E5%9F%9F)
已知函数f(x)=2sin^2x+2√3sinxcosx+a,x属于[π/4,π/2],且f(π/3)=4 1)求实数a的值 2)求函数f(x)的值已知函数f(x)=2sin^2x+2√3sinxcosx+a,x属于[π/4,π/2],且f(π/3)=4 1)求实数a的值 2)求函数f(x)的值域
已知函数f(x)=2sin^2x+2√3sinxcosx+a,x属于[π/4,π/2],且f(π/3)=4 1)求实数a的值 2)求函数f(x)的值
已知函数f(x)=2sin^2x+2√3sinxcosx+a,x属于[π/4,π/2],且f(π/3)=4
1)求实数a的值
2)求函数f(x)的值域
已知函数f(x)=2sin^2x+2√3sinxcosx+a,x属于[π/4,π/2],且f(π/3)=4 1)求实数a的值 2)求函数f(x)的值已知函数f(x)=2sin^2x+2√3sinxcosx+a,x属于[π/4,π/2],且f(π/3)=4 1)求实数a的值 2)求函数f(x)的值域
f(x)=2sin^2x+2√3sinxcosx+a
=1-cos2x+√3sin2x+a
=2sin(2x-π/6)+a+1
(1)当x=π/3时,f(π/3)=2sin(2π/3-π/6)+a+1=4
所以a=1
(2)因为x属于[π/4,π/2],所以2x-π/6属于[π/3,5π/6],
当2x-π/6=π/3时,f(x)=√3+2
当2x-π/6=5π/6时,f(x)=3
当2x-π/6=π/2时,f(x)=4
所以值域为[3,4]
f(x)=2sin^2x+2√3sinxcosx+a
=1-cos2x+√3sin2x+a
=2sin(2x-π/6)+a+1
( 1)当x=π/3时,f(π/3)=2sin(2π/3-π/6)+a+1=4
所以a=1
(2)因为x属于[π/4,π/2],所以2x-π/6属于[π/...
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f(x)=2sin^2x+2√3sinxcosx+a
=1-cos2x+√3sin2x+a
=2sin(2x-π/6)+a+1
( 1)当x=π/3时,f(π/3)=2sin(2π/3-π/6)+a+1=4
所以a=1
(2)因为x属于[π/4,π/2],所以2x-π/6属于[π/3,5π/6],
当2x-π/6=π/3时,f(x)=√3+2
当2x-π/6=5π/6时,f(x)=3
当2x-π/6=π/2时,f(x)=4
所以值域为[3,4] 劳斯莱斯韩国疯狂疯狂
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