A,b,c为有理数,且满足等式a+根号2b+根号3c=根号(5+2倍根号6),则2a+999b+1001c的值是多少
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![A,b,c为有理数,且满足等式a+根号2b+根号3c=根号(5+2倍根号6),则2a+999b+1001c的值是多少](/uploads/image/z/5913721-1-1.jpg?t=A%2Cb%2Cc%E4%B8%BA%E6%9C%89%E7%90%86%E6%95%B0%2C%E4%B8%94%E6%BB%A1%E8%B6%B3%E7%AD%89%E5%BC%8Fa%EF%BC%8B%E6%A0%B9%E5%8F%B72b%EF%BC%8B%E6%A0%B9%E5%8F%B73c%EF%BC%9D%E6%A0%B9%E5%8F%B7%EF%BC%885%EF%BC%8B2%E5%80%8D%E6%A0%B9%E5%8F%B76%EF%BC%89%2C%E5%88%992a%EF%BC%8B999b%EF%BC%8B1001c%E7%9A%84%E5%80%BC%E6%98%AF%E5%A4%9A%E5%B0%91)
A,b,c为有理数,且满足等式a+根号2b+根号3c=根号(5+2倍根号6),则2a+999b+1001c的值是多少
A,b,c为有理数,且满足等式a+根号2b+根号3c=根号(5+2倍根号6),则2a+999b+10
01c的值是多少
A,b,c为有理数,且满足等式a+根号2b+根号3c=根号(5+2倍根号6),则2a+999b+1001c的值是多少
a+b√2+c√3=√(3+2√6+2)=√3+√2
所以a=0,b=1,c=1
原式=0+999+1001=2000